The table contains the percentage of woman receiving prenatal care for a sample of countries. Estimate the average percentage of woman receiving prenatal care using a 90% confidence interval. Round to two decimal places.

Q: Ninety-four percent of students said that cash is their top choice for a graduation gift. If 75…

A: It is given that sample size (n) is 75and the sample proportion value is 0.94.

Q: Wildlife biologists inspect 200 deer taken by hunters and find 45 of them carrying Lyme disease…

A:

Q: In 2016 the CDC wanted to estimate the proportion of adults who are smokers in the U.S. The…

A:

Q: Find the sample size need to find the Population Mean if the margin of error is $105, the confidence…

A: Solution: From the given information, confidence level is 0.95, σ=315 and E=105.

Q: Listed below are the blood pressure measurements taken from the right and left arm of 5 patients.…

A: From the provided information, The mean and standard deviation of the right arm data can be obtained…

Q: Construct a 99.8% confidence interval for the proportion of women who work at home who are college…

A: Given,n=519x=165p^=xnp^=165519=0.318The point estimation for the proportion is 0.318 .

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: 3. A survey of 2,950 Filipinos showed that 2,655 trust the Supreme Court decisions on legal issues.…

A: Let X be the number of trust the supreme court decision on legal issues  n be the sample size  Given…

Q: In a survey, 25 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: You measure 44 textbook's weights, and find they have a mean weight of 81 ounces. Assume the…

A: Answer: From the given data, Sample size(n) = 44 Mean (x¯) = 81 Standard deviation (σ) = 3.8 95%…

Q: Define the confidence level?

A: It is the likelihood of containing the true population parameter under the confidence interval when…

Q: n your random sample of home prices. To insert a tion" or simply copy and edit the equation in the…

A: Formula : The confidence interval formula is CI =

Q: Suppose you calculate a 99% confidence interval to be: 13.05 to 20.75. Determine the margin of error

A: Given data: The given upper limit is b=20.75. The given lower limit is a=13.05.   The expression for…

Q: The General Social Survey asked 1294 people whether they performed any volunteer work during the…

A:

Q: In a survey of 2004 adults in a recent​ year, 717 made a New​ Year's resolution to eat healthier.…

A:

Q: Determine the sample size for a on-line survey with a variability of 30% and a 95% confidence…

A: Sample size n=z2(p*q)/e2

Q: Assume the World Health Organization believes that physician access has an effect on life…

A: 1. The regression R-squared is given as 0.4741.

Q: In a sample of 110 adults, 76 had children. Construct a 95% confidence interval for the true…

A: It is given that, in a sample of 110 adults, 76 had children. It is needed to find a 95% confidence…

Q: in a survey of 2042 adults in a recent​ year, 715 made a New​ Year's resolution to eat healthier.…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A: Given X=25 n=500 95% confidence interval

Q: What proportion of your confidence intervals include the true population mean? Is this proportion…

A: Consider a confidence interval of 95%. That is, the proportion that the confidence interval will…

Q: You measure 38 textbook's weights, and find they have a mean weight of 78 ounces. Assume the…

A: Answer: Using the given data, Sample size (n) = 38 Sample mean x¯ = 78 Population standard deviation…

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: You measure 41 backpacks' weights, and find they have a mean weight of 50 ounces. Assume the…

A: Since we know population standard deviation, Use z-distribution to find z-critical value. Find…

Q: ed 1294 people whether they performed any volunteer work during the past year. A total of 517 people…

A: The sample proportion is computed as follows,

Q: Recently, the Graduate School of Muamalat (GSM) has encouraged the lecturers to attend an online…

A: Given,sample size (n)=20sample mean(x)=51.5standard deviation(s)=6.84028degrees of…

Q: lculating the confidence interval.

A: x Freq 1 3 2 5 3 19 4 7 5 6 Total 40

Q: n a survey, 25 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=25Mean(x)=38standard deviation(s)=19confidence interval(c)=98%

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.

Q: A poll asked for people's opinion on whether closing local newspapers would hurt civic life. 425 of…

A: We have given that, Favorable cases (X) = 425 and sample size (N) = 1002  Then,  We will fins the…

Q: In general, when you increase the confidence level for a confidence interval using the same sample…

A: As confidence level increases critical value is going to increase .  Here they given sample…

Q: Convert the estimate and your confidence interval to Percents. Discuss reasons the estimate might be…

A: We have to convert the estimate and confidence interval into the percentage.

Q: What is the confidence interval? Select the correct choice below and, if necessary, fill in the…

A: Mean = 56.64 Standard deviation = 14.598 n=100

Q: Determine the margin of error. It has been determined with 95% confidence that the proportion of…

A: Given: 95% confidence interval is (0.78, 0.82) So, Lower limit = 0.78 Upper limit = 0.82

Q: You measure 31 backpacks' weights, and find they have a mean weight of 77 ounces. Assume the…

A: Since we know population standard deviation, Use z-distribution to find z-critical value. Find…

Q: magine that you conduct a study and estimate that the prevalence of hypertension among employees of…

A: From the provided information, Sample proportion (p̂) = 0.24 Margin of error for a 95% confidence…

Q: Find the margin of​ error, using a​ 95% confidence​ level, for estimating the percentage of all…

A: Given:- simple random sample of 1200 young people  so, n= 1200 86% had earned a high school diploma…

Q: 4- Dissolved oxygen concentrations were measured at 8 different points in a reservoir and…

A: Assume a random variable X to represent the considered oxygen concentrations. Determine the sample…

Q: Describe when you would use a t-score instead of a z-score when finding a confidence interval.

A: Describe in what conditions t-score would be used instead of a z-score when finding a confidence…

Q: According to a telephone survey of adults, 86% of homeowners said that owning a home was a good…

A: From the given information, According to a telephone survey of adults, 86% of homeowners said that…

Q: A quality control specialist wants to estimate the percentage of defective batteries within 5% from…

A: A quality control specialist wants to estimate the percentage of defective within 5% from the true,…