**Probability Distribution of Daily Coffee Breaks of Coffee Drinkers**The table below shows the probability distribution for $ X $, the number of daily coffee breaks taken per day by coffee drinkers. The objective is to determine the expected number of daily coffee breaks taken per day by coffee drinkers.| $ x $ | $ f(x) $ ||--------|------------|| 0 | 0.40 || 1 | 0.20 || 2 | 0.15 || 3 | 0.10 || 4 | 0.08 || 5 | 0.07 |To calculate the expected number of daily coffee breaks, you can use the formula for the expected value $ E(X) $:\[ E(X) = \sum (x \cdot f(x)) \]Given the choices:- 2.50- 2.35- 3.79- 1.47- 1.36Complete the calculation to identify the correct expected value from the provided options.

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Answered: The table below shows the probability…

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter12: Probability

Section12.2: Introduction To Probability

Problem 34E

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The table below shows the probability distribution for X, the number of daily coffee breaks taken per day by coffee drinkers. What is the expected number of daily coffee breaks taken per day by coffee drinkers? 2.50 2.35 3.79 1.47 1.36 X 0 1 2 3 4 5 f(x) 0.40 0.20 0.15 0.10 0.08 0.07