The table below shows the distribution of test grades for 50 IB students at Greendale School 32 65 60 35 Test grade Frequency 1 1 6 2 3 21 3 7 4 13 (a) Calculate (i) the mean test grade of the students; 5= (ii) the standard deviation. SD= (b) Find the median test grade of the students. 50÷2=25 Σ(x-2) n=1 5 11 (c) Find the interquartile range. IOR= Q1-Q2 → Sum of all terms number of terms 230 (11-4.6) 2 50-1 25th 25th value = 5 6 10 7 5 230=4.6 50 ⇒SD = 13.86
The table below shows the distribution of test grades for 50 IB students at Greendale School 32 65 60 35 Test grade Frequency 1 1 6 2 3 21 3 7 4 13 (a) Calculate (i) the mean test grade of the students; 5= (ii) the standard deviation. SD= (b) Find the median test grade of the students. 50÷2=25 Σ(x-2) n=1 5 11 (c) Find the interquartile range. IOR= Q1-Q2 → Sum of all terms number of terms 230 (11-4.6) 2 50-1 25th 25th value = 5 6 10 7 5 230=4.6 50 ⇒SD = 13.86
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Transcribed Image Text:The table below shows the distribution of test grades for 50 IB students at Greendale School
65
60
35
Test grade
Frequency
1
1
6
2
3
21
3
7
(a) Calculate
(i) the mean test grade of the students; *=
(ii) the standard deviation. SD=(x-x
n=1
4
13
5
11
6
10
sum of all terms.
number of terms
230 (11-4.6) ²
50-1
(b) Find the median test grade of the students.
50÷2=250 25th value
→
= 5
(c) Find the interquartile range. IOR= Q1-Q2
A student is chosen at random from these 50 students.
7
5
230⇒x=4.6
50
⇒ SD = 13.86
I
E
[(d) Find the probability that this student scored a grade 5 or higher.
A second student is chosen at random from these 50 students.
(e) Given that the first student chosen at random scored a grade 5 or higher, find the proba
that both students scored a grade 6.
L
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