The table below gives the stopping distance y (in 100 meters) for a train traveling on a track at various speeds x (miles per hour). Speed, x (mi/h) Distance, y (100 m) 50 55 60 65 70 75 80 85 90 20 25 35 50 70 95 125 160 200 Find an equation of the quadratic function that models the data, and predict the stopping distance for the train traveling at 95 miles per hour. O y - 0.12² - 9.5x + 245 about 2050 hundred meters O y= 0.1x* + 9.5x+ 245 about 245 hundred meters O There is no correct answer given. O y= 0.1x² + 9.5x+ 245 about 2050 hundred meters O y= 0.1x² – 9.5x+ 245 about 245 hundred meters

The table below gives the stopping distance y (in 100 meters) for a train traveling on a track at various speeds x (miles per hour). Speed, x (mi/h) Distance, y (100 m) 50 55 60 65 70 75 80 85 90 20 25 35 50 70 95 125 160 200 Find an equation of the quadratic function that models the data, and predict the stopping distance for the train traveling at 95 miles per hour. O y - 0.12² - 9.5x + 245 about 2050 hundred meters O y= 0.1x* + 9.5x+ 245 about 245 hundred meters O There is no correct answer given. O y= 0.1x² + 9.5x+ 245 about 2050 hundred meters O y= 0.1x² – 9.5x+ 245 about 245 hundred meters

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differential equations.

Question

The table below gives the stopping distance y (in 100 meters) for a train traveling on a track at
various speeds x (miles per hour).
Speed, x
(mi/h)
Distance, y
(100 m)
50
55
60
65
70
75
80
85
90
20
25
35
50
70
95
125
160
200
Find an equation of the quadratic function that models the data, and predict the stopping distance
for the train traveling at 95 miles per hour.
O y = 0.1x2 - 9.5x+ 245
about 2050 hundred meters
y = 0.12 + 9.5x + 245
about 245 hundred meters
O There is no correct answer given.
y = 0.1x* + 9.5x + 245
about 2050 hundred meters
y = 0.1x - 9.5x+ 245
about 245 hundred meters

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