The system of first order differential equations: ไม่ โ = = -8 y₁+ 2 y2, 52 1 + 12 32, 31 (0) = −4 32(0) = -25
The system of first order differential equations: ไม่ โ = = -8 y₁+ 2 y2, 52 1 + 12 32, 31 (0) = −4 32(0) = -25
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Ive asked this quesrion 4 times now and theyve all been wrong
![has solution:
yı(t)
Y₂(t)
Entered
[e^(2*t)]*[-4*cos(2)*t-5*sin (2)*t]
At least one of the answers above is NOT correct.
=
[e^(2*t)]*[-25*cos(2)*t-21*sin(2)*t]
The system of first order differential equations:
e2t (-4 cos 2t - 5 sin 2t)
e²t (-25 cos 2t - 21 sin 2t)
Note: You must express the answer in terms of real numbers only.
[3₁
13/12
-8 y₁+2 Y2,
-52 yı + 12 y2,
Answer Preview
e²t (4 cos(2) t — 5 sin(2)t)
e²t (-25 cos (2)t – 21 sin(2)t)
y₁ (0) = -4
Y₂ (0) = -25
Result
incorrect
incorrect](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F94884f69-365e-43dc-a457-f3f8066ccdfc%2F4fb5e0f2-30db-40da-8f47-4ca8af912223%2Faljrt5e_processed.png&w=3840&q=75)
Transcribed Image Text:has solution:
yı(t)
Y₂(t)
Entered
[e^(2*t)]*[-4*cos(2)*t-5*sin (2)*t]
At least one of the answers above is NOT correct.
=
[e^(2*t)]*[-25*cos(2)*t-21*sin(2)*t]
The system of first order differential equations:
e2t (-4 cos 2t - 5 sin 2t)
e²t (-25 cos 2t - 21 sin 2t)
Note: You must express the answer in terms of real numbers only.
[3₁
13/12
-8 y₁+2 Y2,
-52 yı + 12 y2,
Answer Preview
e²t (4 cos(2) t — 5 sin(2)t)
e²t (-25 cos (2)t – 21 sin(2)t)
y₁ (0) = -4
Y₂ (0) = -25
Result
incorrect
incorrect
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