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The system of first order differential equations: ไม่ โ = = -8 y₁+ 2 y2, 52 1 + 12 32, 31 (0) = −4 32(0) = -25

The system of first order differential equations: ไม่ โ = = -8 y₁+ 2 y2, 52 1 + 12 32, 31 (0) = −4 32(0) = -25

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Ive asked this quesrion 4 times now and theyve all been wrong

has solution: yı(t) Y₂(t) Entered [e^(2*t)]*[-4*cos(2)*t-5*sin (2)*t] At least one of the answers above is NOT correct. = [e^(2*t)]*[-25*cos(2)*t-21*sin(2)*t] The system of first order differential equations: e2t (-4 cos 2t - 5 sin 2t) e²t (-25 cos 2t - 21 sin 2t) Note: You must express the answer in terms of real numbers only. [3₁ 13/12 -8 y₁+2 Y2, -52 yı + 12 y2, Answer Preview e²t (4 cos(2) t — 5 sin(2)t) e²t (-25 cos (2)t – 21 sin(2)t) y₁ (0) = -4 Y₂ (0) = -25 Result incorrect incorrect
Transcribed Image Text:has solution: yı(t) Y₂(t) Entered [e^(2*t)]*[-4*cos(2)*t-5*sin (2)*t] At least one of the answers above is NOT correct. = [e^(2*t)]*[-25*cos(2)*t-21*sin(2)*t] The system of first order differential equations: e2t (-4 cos 2t - 5 sin 2t) e²t (-25 cos 2t - 21 sin 2t) Note: You must express the answer in terms of real numbers only. [3₁ 13/12 -8 y₁+2 Y2, -52 yı + 12 y2, Answer Preview e²t (4 cos(2) t — 5 sin(2)t) e²t (-25 cos (2)t – 21 sin(2)t) y₁ (0) = -4 Y₂ (0) = -25 Result incorrect incorrect
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