The system of first order differential equations: = −13 31+2 32, 31(0) = 1 โม = -34 y1 + 3y2, 32(0) = 3 Y1(t) has solution: = e-5 (cos(2t) - sin(2t)) Y2(t) = e-5 (cos(2t) + sin(2t)) ⑨ Note: You must express the answer in terms of real numbers only.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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hi im on my last attempt for this question. please help! the first one is right but the second is wrong :( 

The system of first order differential equations:
=
−13 31+2 32,
31(0) = 1
โม
=
-34 y1 + 3y2,
32(0) = 3
Y1(t)
has solution:
=
e-5 (cos(2t) - sin(2t))
Y2(t)
=
e-5 (cos(2t) + sin(2t))
⑨
Note: You must express the answer in terms of real numbers only.
Transcribed Image Text:The system of first order differential equations: = −13 31+2 32, 31(0) = 1 โม = -34 y1 + 3y2, 32(0) = 3 Y1(t) has solution: = e-5 (cos(2t) - sin(2t)) Y2(t) = e-5 (cos(2t) + sin(2t)) ⑨ Note: You must express the answer in terms of real numbers only.
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