The synthesis given below for m-propylbenzene from benzene is incorrect. Propose a suitable synthesis to accomplish this transformation.

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The synthesis given below for m-propylbenzene from benzene is incorrect. Propose a
suitable synthesis to accomplish this transformation.

 

The image depicts a two-step organic reaction sequence involving aromatic compounds. Below is a detailed explanation of each step:

1. **Nitration of Benzene:**
   - **Starting Material:** Benzene (C₆H₆)
   - **Reagents:** Nitric acid (HNO₃) and sulfuric acid (H₂SO₄)
   - **Product:** Nitrobenzene (C₆H₅NO₂)
   - **Description:** In this step, a benzene ring undergoes nitration, where a nitro group (NO₂) is introduced to the aromatic ring. Sulfuric acid acts as a catalyst to facilitate this electrophilic substitution reaction.

2. **Friedel-Crafts Alkylation:**
   - **Starting Material:** Nitrobenzene (C₆H₅NO₂)
   - **Reagents:** Propyl chloride (CH₃CH₂CH₂Cl) and aluminum chloride (AlCl₃)
   - **Product:** 1-nitro-4-propylbenzene
   - **Description:** In this step, the nitrobenzene undergoes Friedel-Crafts alkylation, where a propyl group (CH₂CH₂CH₃) is added to the aromatic ring. Aluminum chloride is used as a catalyst to generate the electrophile, facilitating the attachment of the propyl group to the benzene ring, producing 1-nitro-4-propylbenzene.

This reaction sequence highlights typical transformations in aromatic chemistry, emphasizing the utility of electrophilic aromatic substitution reactions in organic synthesis.
Transcribed Image Text:The image depicts a two-step organic reaction sequence involving aromatic compounds. Below is a detailed explanation of each step: 1. **Nitration of Benzene:** - **Starting Material:** Benzene (C₆H₆) - **Reagents:** Nitric acid (HNO₃) and sulfuric acid (H₂SO₄) - **Product:** Nitrobenzene (C₆H₅NO₂) - **Description:** In this step, a benzene ring undergoes nitration, where a nitro group (NO₂) is introduced to the aromatic ring. Sulfuric acid acts as a catalyst to facilitate this electrophilic substitution reaction. 2. **Friedel-Crafts Alkylation:** - **Starting Material:** Nitrobenzene (C₆H₅NO₂) - **Reagents:** Propyl chloride (CH₃CH₂CH₂Cl) and aluminum chloride (AlCl₃) - **Product:** 1-nitro-4-propylbenzene - **Description:** In this step, the nitrobenzene undergoes Friedel-Crafts alkylation, where a propyl group (CH₂CH₂CH₃) is added to the aromatic ring. Aluminum chloride is used as a catalyst to generate the electrophile, facilitating the attachment of the propyl group to the benzene ring, producing 1-nitro-4-propylbenzene. This reaction sequence highlights typical transformations in aromatic chemistry, emphasizing the utility of electrophilic aromatic substitution reactions in organic synthesis.
Expert Solution
Step 1

In nitrobenzene , nitro group is deactivating group so it deactivates benzene ring and it not give desired product by F.C. alkylation. 

Propyl group is activating and ortho -para directing so we can't formed desired product if we performed nitration reaction on propylbenzene.

So, let's make another route.

 

 

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