The switch has been in the left position for a long time. At tt = 0, it moves to the right position and stays. What is the initial voltage drop across the capacitor? What is the initial energy stored by the capacitor? Find the time constant of this circuit for t> 0.
The switch has been in the left position for a long time. At tt = 0, it moves to the right position and stays. What is the initial voltage drop across the capacitor? What is the initial energy stored by the capacitor? Find the time constant of this circuit for t> 0.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question
The switch has been in the left position for a long time. At tt = 0, it moves to the right position and stays.
What is the initial voltage drop across the capacitor?
What is the initial energy stored by the capacitor?
Find the time constant of this circuit for t> 0.
Transcribed Image Text:The image shows an electrical circuit diagram which includes a DC voltage source, resistors, a capacitor, and a switch.
- The voltage source on the left side is labeled as 150 V.
- To the right of the voltage source is a 10 kΩ resistor connected in series.
- Next, in line, is a switch that is initially open and connected to a 5 kΩ resistor.
- Below the switch is a capacitor with a capacitance of 40 nF, and it has a voltage across it labeled as \( v \).
- The switch position changes at \( t = 0 \).
- The circuit continues with two resistors, 30 kΩ and 60 kΩ, which are connected in parallel to each other to the right of the 5 kΩ resistor.
This circuit diagram can be used to analyze and understand the behavior of an RC circuit when the switch is closed at \( t = 0 \), allowing students to explore charging and discharging phases of the capacitor, as well as the impact of resistor values on time constants.
Expert Solution
Step 1
In the given circuit switch is at position-1 for a long time. So, that the capacitor gets charged to the source voltage.
When the switch is moved to position-2 (right), the circuit will be source free.
Hence, the capacitor voltage gets discharged through the resistances.
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