The switch below has been closed for a long period of time and is opened att=0.Switch_open_t=0a) Find the ENERGY stored in thecapacitor just before theswitch is opened6kQ1ka1kQ12V1µFThe switch opens att=0. Thecapacitor begins to discharge.Q(t)c = Q(0). · eb) At what time 't will the charge on the capacitor be equal to 20% of thecharge at t=0?c) How much charge remains on the capacitor at this time?d) Find the total energy dissipated by one of the 1k2 resistors usingE, = p(t)dt where p(t)is the instantaneous power

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Answered: The switch below has been closed for a…

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Question 2: #46 With the switch open, the potential difference across the capacitor in Figure below is 10.0 V. After the switch is closed, how long will it take for the potential difference across the capacitor to decrease to 5.0 V?
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Suppose the following circuit is left open for a long time. 24 V- 5000 Ω 80 mF (a) What is the charge on the capacitor 90s after we close the switch? (b) What is the potential difference across the capacitor 90s after we close the switch? (c) What is the potential difference across the resistor 90s after we close the switch?
Physics Question: Please take a look at this question and answer the following! Thank you so much!
A parallel plate capacitor used in a flash for a camera must be able to store 16.0 J of energy when connected to 309 V. (Most electronic flashes actually use a 1.50- to 6.00-V battery, but increase the effective voltage using a dc–dc inverter.) What should be the capacitance of this capacitor?
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With the switch open, the potential difference across the capacitor shown is 10.0 V. After the switch is closed, how long will it take for the potential difference across the capacitor to decrease to 5.0 V?