The surface integral xyzdS, where S is the portion of the cylinder y+z = a² (a >0), in the first octant, between the planes x 0, x=9, z=y, and z=2y, is equal to Select one: N *ydydx alN5 o r1//2 x²ydydx a Ssydydk alNE ydxdy -al5 ONone of these

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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The surface integral xyzds, where S is the portion of the cylinder y+z? = a? (a >0),
in the first octant, between the planes x=0, x= 9, z= y, and z=2y, is equal to
Select one:
N*ydydx
al5 o
1//2
ydydx
afSydydx
o al5
9 ral2
x²ydxdy
-a/5
O None of these
:-
Transcribed Image Text:The surface integral xyzds, where S is the portion of the cylinder y+z? = a? (a >0), in the first octant, between the planes x=0, x= 9, z= y, and z=2y, is equal to Select one: N*ydydx al5 o 1//2 ydydx afSydydx o al5 9 ral2 x²ydxdy -a/5 O None of these :-
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