Upload a PDF document that shows your work and solution.The Sun has a luminosity of L = 3.846 × 1026 W, and a radius of Rs = 697,000 km. Working withR²L=the inverse-square law for intensities, Io R²and the surface-intensity of the Sun as ITTR1how much power would a 12.0 m² solar panel collect on Earth as compared to that when used on a? Take the distance from the Sun toPJupiterPEarthGalilean moon of Jupiter - in short, what is the ratioEarth as RE = 1.49 x 10⁹ m and from the Sun to a Galiena moon as RJ=7.78 x 10⁹ m, andthe power formula is P= I. A where I is the intensity of light at a given distance from the Sun,and A is the area of the solar panel.

Answered: Image /qna-images/answer/ee944b1d-ca67-487e-b6d2-bd6b0fd9a66c.jpg

The Sun has a luminosity of L = 3.846 x 1026 W, and a radius of Rs = 697,000 km. Working with L the inverse-square law for intensities, R² = , and the surface-intensity of the Sun as I R²¹ = TR how much power would a 12.0 m² solar panel collect on Earth as compared to that when used on a PJupiter ? Take the distance from the Sun to PEarth = 7.78 x 10⁹ m, and - in short, what is the ratio Galilean moon of Jupiter Earth as RE = 1.49 x 10⁹ m and from the Sun to a Galiena moon as RJ the power formula is P= I. A where I is the intensity of light at a given distance from the Sun, and A is the area of the solar panel.

The Sun has a luminosity of L = 3.846 x 1026 W, and a radius of Rs = 697,000 km. Working with L the inverse-square law for intensities, R² = , and the surface-intensity of the Sun as I R²¹ = TR how much power would a 12.0 m² solar panel collect on Earth as compared to that when used on a PJupiter ? Take the distance from the Sun to PEarth = 7.78 x 10⁹ m, and - in short, what is the ratio Galilean moon of Jupiter Earth as RE = 1.49 x 10⁹ m and from the Sun to a Galiena moon as RJ the power formula is P= I. A where I is the intensity of light at a given distance from the Sun, and A is the area of the solar panel.