The Sun cranks out about 4 x 1026 J/s, i.e. its radiant power pe = 4 x 10²6 W. For a square meter of area here on the Earth whose surface normal points directly to the Sun, how many watts are received? How many 550-nm photons would that correspond to? (The Earth-Sun distance is about 150x106 km.)
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The energy radiated by sun is spread over the shperical surface with sun as center. So to calculate energy incident on earth's surface, we first calculate the surface area at earth-sun distance. The steps are given below.
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- Suppose a star with radius 8.57 × 108 m has a peak wavelength of 680 nm in the spectrum of its emitted radiation. (a) Find the energy of a photon with this wavelength. J/photon (b) What is the surface temperature of the star? K (c) At what rate is energy emitted from the star in the form of radiation? Assume the star is a blackbody (e = 1). W (d) Using the answer to part (a), estimate the rate at which photons leave the surface of the star. photons/sA typical red laser pointer has a power output of 1.50 mW and a wavelength of 680 nm. Find how many photons per second the laser emits in units of 10¹5 photons/sec. (A) 2.31 (B) 5.13 (C) 4.97 (D) 7.49 (E) 3.78For light with a wavelength of 350 nm and with an intensity of /= 10-8 W/m², what is the number of photons/(m²s) in the light beam?
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