My teacher has asked me to make a menu that will veryify the check digit of a ISBN number and I can't make sense of the instructions. The Program needs to check the ISBN 10 check number ISBN 13 Check number and change the ISBN 10 to a 13 and a 13 to 10. Then Exit. I don't even have an Idea where to start. The sum must be divisible by 10 for a thirteen digit ISBN. The check digit 5 was chosen because115 divided by 10 is 11 with remainder 5. The remainder is the check digit. Thus we have:A thirteen digit ISBN number: 978-0-13-149498-5.Write a python program which displays a simple menu as follows:Python ISBN Conversion Menu1.Verify the check digit of an ISBN-102.Verify the check digit of an ISBN-133.Convert an ISBN-10 to an ISBN-134.Convert an ISBN-13 to an ISBN-105.ExitPlease remember to use what you have learned during the semester such as:Functions and/or Value Returning FunctionsIf structures or logic structures IF/Elif/ELSEData structures i.e. File input/outputString manipulations i.e. string slicing and lists, etc.ModulesLoops i.e. WHILE loops or FOR loops Ten digit ISBN numbers are created so that the first nine digits are information digits and the lastdigit is a check digit. This last number helps people notice and correct mistakes that might bemade in recording the information digits. The same is true for thirteen digit ISBN numbers. Hereis a ten digit ISBN number: 0-13-149498-8. The digit 0 indicates the book is written for English-speaking people. The number 13 and the number 149498 identify the publisher and the bookpublished by that publisher. The last digit, the 8, is the check digit. It was chosen in the followingway: each digit is given a weight by using the digits 1 to 10 and counting left to right. Theseweights are added. The sum is:0(1) + 1(2) +3(3) + 1(4) + 4(5) + 9(6) + 4(7) + 9(8) + 8(9)+.(The digits of the ISBN information numbers are listed in order from left to right and weightedby counting up from 1 to 9.) The check digit is chosen to be a number from 0 to 10 so that thisweighted sum is a multiple of 11. That is, the sum must be divisible by 11. (If the check digitturns out to be 10 then in this case an X is displayed representing the Roman numeral for 10.)Let us see what sum we have so far with these particular nine information digits:0(1) + 1(2) +3(3) + 1(4) + 4(5) + 9(6) +4(7) + 9(8) + 8(9)= 0 +2 +9 +4 + 20 + 54 + 28 + 72 + 72= 261The check digit 8 was chosen because 261 is between 253 and 264 (multiples of 11) and 261 is 8more than 253. The only possible number from 0 to 10 to use as a check digit is 8. Thus we have:A ten digit ISBN number: 0-13-149498-8If you know the ten digit ISBN number you can calculate the thirteen digit ISBN number.Simply start the thirteen digit ISBN number with 978, then re-calculate the check digit. Forexample, 0-13-149498-8 becomes 978-0-13-149498-? Calculating the check digit for the thirteendigit ISBN number is done differently than for the ten digit ISBN number. Below is the way tocalculate the thirteen digit ISBN check digit.Note that on a thirteen digit ISBN number the weighted numbers are different:13131 3 1 3 1 3 1 39(1) + 7(3) + 8(1)+ 0(3) + 1(1) +3(3)+ 1(1) + 4(3) + 9(1) + 4(3) + 9(1) + 8(3)+=9 + 21 + 8 + 0 + 1 + 9 + 1 + 12 + 9 + 12 + 9+24=115

Actually, python is a easiest programming language It is a dynamically typed programming language.def main(): menu() def menu(): print('1. Verify the check digit of an ISBN-10') print("2. verify the check digit of an ISBN-13") print("3. Convert an ISBN-10 to an ISBN-13") print('4. Convert an ISBN-13 to an ISBN-10') print('5. Exit') command = input("Enter the Command (1-5): ") if command == '5': return elif command == '1' or command == '3': #get 10 digit input ISBN = input("Please enter the 10 digit number: ") while len(ISBN) != 10: print("Please make sure you have entered a number which is exactly 10 characters long.") ISBN = input("Please enter the 10 digit number: ") print(format(ISBN)) if command == '1': print(check_10_digit(ISBN)) else: print(convert_10_to_13(ISBN)) elif command == '2' or command == '4': #get 13 digit input ISBN = input("Please enter the 13 digit number: ") while len(format(ISBN)) != 13: print("Please make sure you have entered a number which is exactly 13 characters long") ISBN = input("Please enter the 13 digit number: ") if command == '2': print(check_13_digit(ISBN)) else: print(convert_13_to_10(ISBN)) #show the menu again menu() def check_10_digit(ISBN): #This portion of code will pull the entered ISBN from the Menu() statement and add all the numbers. #It will then find the remainder of those numbers, if th remainder is 0 it will say the ISBN is valid #If it comes back with the formula having a remainder, it will say NOT Valid. digit = 0 for i in range(len(ISBN)): n = ISBN[i] num = int(n) digit += (i+1) * num d10 = digit % 11 print("Your ISBN-10 is: ", ISBN, "with a remainder of", str(d10)) if d10 == 0: print("Your ISBN-10 is valid") else: print("Your ISBN-10 is NOT valid") def check_13_digit(ISBN): #Calcualte the ISBN Check Digit for 13 digit numbers n = str(ISBN) digit = 0 for i in range(len(n)): if i % 2 == 0: digit += int(n[i]) else: digit += int(n[i]) * 3 digit = digit % 10 if digit == 0: print("Your remainder is: ", digit, "your ISBN-13 is Valid") else: print("Your remainder is: ", digit, "your ISBN-13 is NOT Valid") def convert_10_to_13(ISBN): #Convert an ISBN-10 number to a ISBN-13 number ISBN_13 = '978' + ISBN[:-1] n = str(ISBN_13) digit = 0 for i in range(len(n)): if i % 2 == 0: digit += int(n[i]) else: digit += int(n[i]) * 3 digit = digit % 10 ISBN_New = str(ISBN_13) + str(digit) print("The ISBN-10 number ", ISBN, "is converted to the ISBN-13 number ", ISBN_New) def convert_13_to_10(ISBN): #Convert an ISBN-13 number to a ISBN-10 number if ISBN[:3] == '978': n = str(ISBN[3:-1]) else : raise "ISBN is not convertible." digit = 0 for i in range(len(n)): if i % 2 == 0: digit += int(n[i]) else: digit += int(n[i]) * 3 digit = 10 - (digit % 10) ISBN_New = str(n) + str(digit) print("The ISBN-13 number ", ISBN, "is converted to the ISBN-10 number ", ISBN_New) main()Output :-