The sulfur content of an iron pyrite ore sample is determined by converting it to H2Sgas, absorbing the H2S in 10.0mL of 0.00500 M I2, and then back-titrating the excess 12with 0.00200 M Na2S203. If 2.6mL Na2S20zis required for the titration, how many milligramsof sulfur are contained in the sample? (Mwt of H2S is 34.08g/mol).Reactions:H2S + I2-------> S+21 + 2H*I2+ 2S20,2----------> 21- + S,0,2-I()II!!

H2S + I2 ----> S + 2I- + 2H+ I2 + 2S2O3-2 ----> 2I- + S4O6-2 Valency factor of H2S = 2 (O.S…

The sulfur content of an iron pyrite ore sample is determined by converting it to H2S gas, absorbing the H2S in 10.0mL of 0.00500 M I2, and then back-titrating the excess 12 with 0.00200 M Na,S203. If 2.6mL Na2S203is required for the titration, how many milligrams of sulfur are contained in the sample? (Mwt of H2S is 34.08g/mol). Reactions: H2S + I2 ---- > S+ 21" + 2H* I2+ 2S20,2- ---------> 21- + S,0,2-

The sulfur content of an iron pyrite ore sample is determined by converting it to H2S gas, absorbing the H2S in 10.0mL of 0.00500 M I2, and then back-titrating the excess 12 with 0.00200 M Na,S203. If 2.6mL Na2S203is required for the titration, how many milligrams of sulfur are contained in the sample? (Mwt of H2S is 34.08g/mol). Reactions: H2S + I2 ---- > S+ 21" + 2H* I2+ 2S20,2- ---------> 21- + S,0,2-

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

The sulfur content of an iron pyrite ore sample is determined by converting it to H2S
gas, absorbing the H2S in 10.0mL of 0.00500 M I2, and then back-titrating the excess 12
with 0.00200 M Na2S203. If 2.6mL Na2S20zis required for the titration, how many milligrams
of sulfur are contained in the sample? (Mwt of H2S is 34.08g/mol).
Reactions:
H2S + I2
-------> S+21 + 2H*
I2+ 2S20,2-
---------> 21- + S,0,2-
I
()
II
!!

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