The sugar content of the syrup in canned peaches is assumed normally distributed. A random sample is taken, and the measurements of the sugar content areshown as follows.Sugar Content of the Syrup (mg)39.042.236.243.936.138.443.144,631.246.8(a) The 95% confidence interval on standard deviation of sugar content is type your answer...decimal placestype your answer.....(b) If the inspector wants to control estimation error on a within 2 mg. the minimum sample size is type your answer...). Round answer to two

The provided information is as follows:The level of confidence is .The sample size is .The margin of…

Answered: The sugar content of the syrup in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Safe You wish to test the following claim (Ha) at a significance level of a = 0.001. H.:u = 81.6 Ha:p # 81.6 No Inst You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: Column A Column B Column C Column D Column E HPS Ass 86.6 83.3 100.9 82.4 80.4 85 69.1 79.8 79.3 75.3 88.5 76.3 79.8 75.5 76.5 cha 80 65.9 94.9 73.9 72 73.3 77.5 97 84.5 84.5 82.9 80.9 70.5 83.8 76.3 78.4 94.1 94.9 88.8 94.1 91.2 76.5 88.1 94.1 71.7 82.9 87.8 80 86.6 92.8 81.1 80.9 91.2 80.2 84 88.5 88.5 72.4 83.8 70.1 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value =
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
You are interested in finding a 90% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 14 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 5 8 11 10 12 19 24 6 26 10 26 10 26 15 a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean commute for non-residential college students is between and miles. c. If many groups of 14 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of commute miles and about percent will not contain the true population mean number of commute miles.
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
Score last try: pts. See Details for more. You can retry this question below For a 4-unit class like Statistics, students should spend average of 12 hours studying for the class. A survey was done on 28 students, and the distribution of total study hours per week is bell-shaped with a mean of 13 hours and a standard deviation of 3.1 hours. Use the Empirical Rule to answer the following questions. a) 68% of the students spend between 12.41 X hours and 13.58 x hours on Statistics each week. b) 95% of the students spend between 11.82 X hours and 14.7 X hours on Statistics each week. c) 99.7% of the students spend between 11.24 X hours and 14.76 X hours on Statistics each week.
The incomes of trainees at a local mill are normally distributed with a mean of $1,100 and a standard deviation of $150. What percentage of trainees earn more than $1,300 a month? Group of answer choices 9.18% 40.82% 90.82% 35.31%
I need an APA write up description of the descriptives of this data set of the number of male and females who preferred hamburgers or hot dogs. (EXAMPLE: “The total sample was n=…, demographic breakup is ......The mean was...the Standard Deviation was…”) etc.

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