The subscript refers to the resistor with that value I. Find the equivalent resistance in these network of resistors. Req= ◆ Ω 2.00 Ω AWWW 6.00 Ω ww 4.00 Ω 3.00 Ω B ww 13.00 Ω II. Find the current in each resistors when a 50-volt battery is connected across point A and B. I₁ = A 1₂ 109/23 975/218 I3 = 450/109 725/218 I4 = 3150/109 2300/109 16 = 325/109 975/109 I12 1150/109 2175/109 I13 1575/218 75/218 A A A A A A 1.00 Ω ww 12.00 Ω

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The subscript refers to the resistor with that value
I. Find the equivalent resistance in these network of resistors.
Req=
◆ Ω
2.00 Ω
AWWW
6.00 Ω
ww
4.00 Ω
3.00 Ω
B
ww
13.00 Ω
II. Find the current in each resistors when a 50-volt battery is connected across point A and B.
I₁ =
A
1₂
109/23
975/218
I3 =
450/109
725/218
I4 = 3150/109
2300/109
16 = 325/109
975/109
I12
1150/109
2175/109
I13 1575/218
75/218
A
A
A
A
A
A
1.00 Ω
ww
12.00 Ω
Transcribed Image Text:The subscript refers to the resistor with that value I. Find the equivalent resistance in these network of resistors. Req= ◆ Ω 2.00 Ω AWWW 6.00 Ω ww 4.00 Ω 3.00 Ω B ww 13.00 Ω II. Find the current in each resistors when a 50-volt battery is connected across point A and B. I₁ = A 1₂ 109/23 975/218 I3 = 450/109 725/218 I4 = 3150/109 2300/109 16 = 325/109 975/109 I12 1150/109 2175/109 I13 1575/218 75/218 A A A A A A 1.00 Ω ww 12.00 Ω
4.00 Ω
3.00 Ω
12.00 Ω
B
www
13.00 Ω
II. Find the current in each resistors when a 50-volt battery is connected across point A and B.
I₁ =
A
1₂. =
A
I3 =
◆ A
◆ A
14 =
16 =
A
♦
A
I12 =
I13 =
◆ A
III. Find the voltage across each resistors when a 50-volt battery is connected across point A
and B.
V₁ =
◆ V
V₂ =
→ V
V3 =
◆ V
V4=
◆ V
V6 =
◆ V
V12 =
V13 =
V
♦ V
Transcribed Image Text:4.00 Ω 3.00 Ω 12.00 Ω B www 13.00 Ω II. Find the current in each resistors when a 50-volt battery is connected across point A and B. I₁ = A 1₂. = A I3 = ◆ A ◆ A 14 = 16 = A ♦ A I12 = I13 = ◆ A III. Find the voltage across each resistors when a 50-volt battery is connected across point A and B. V₁ = ◆ V V₂ = → V V3 = ◆ V V4= ◆ V V6 = ◆ V V12 = V13 = V ♦ V
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