The structure of A is shown below. Но з -CH2CH=CH2 A (1) Predict the possible number of stereoisomers A can have. (ii) Draw the 3D structure of the (2S, 3R, 55) enantiomer showing its correct stereochemistry. (iii) Calculate the specific rotation of each enantiomer in a mixture containing 10 mL (0.10 M) of (2S, 3R, 5S) enantiomer and 30 mL (0.10 M) of (2R, 3S, 5R) enantiomer. Given the specific rotation of the mixture = +4.8°.

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The structure of A is shown below.
HO 3
-CH2CH=CH2
A
(i) Predict the possible number of stereoisomers A can have.
(ii) Draw the 3D structure of the (25, 3R, 5S) enantiomer showing its correct stereochemistry.
(iii) Calculate the specific rotation of each enantiomer in a mixture containing 10 mL (0.10 M) of (2S, 3R, 55) enantiomer and 30 mL (0.10 M) of (2R, 3S, 5R)
enantiomer. Given the specific rotation of the mixture = +4.8°.
Transcribed Image Text:The structure of A is shown below. HO 3 -CH2CH=CH2 A (i) Predict the possible number of stereoisomers A can have. (ii) Draw the 3D structure of the (25, 3R, 5S) enantiomer showing its correct stereochemistry. (iii) Calculate the specific rotation of each enantiomer in a mixture containing 10 mL (0.10 M) of (2S, 3R, 55) enantiomer and 30 mL (0.10 M) of (2R, 3S, 5R) enantiomer. Given the specific rotation of the mixture = +4.8°.
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