The stresses shown act at a point in a stressed body. Normal and shear stress magnitudes acting on horizontal and vertical planes at the point are Sx = 27 MPa, Sy = 31 MPa, and Sxy = 32 MPa. Assume β=tan−1(ba)=11.3∘β=tan-1(ba)=11.3∘, a = 5, and b = 1. Using the equilibrium equation approach, determine the normal and shear stresses σσ (positive if tensile, negative if compressive) and ττ (magnitude only) at this point on the inclined plane shown. The stresses shown act at a point in a stressed body. Normal and shear stress magnitudes acting on horizontal and vertical planes at= 11.3°, a = 5, and b = 1. Using the equilibriumthe point are Sy = 27 MPa, Sy = 31 MPa, and Syy = 32 MPa. Assume ß = tan¬!equation approach, determine the normal and shear stresses o (positive if tensile, negative if compressive) and z (magnitude only) atthis point on the inclined plane shown.|SySxyAnswers:MPа.MPa, t =

Sx= 27 MPaSy= 31 MPaSxy= 32 MPaβ= 11.3∘

The stresses shown act at a point in a stressed body. Normal and shear stress magnitudes acting on horizontal and vertical planes at the point are Sy = 27 MPa, S, = 31 MPa, and Sy = 32 MPa. Assume ß = tan¬1 = 11.3°, a = 5, and b = 1. Using the equilibrium equation approach, determine the normal and shear stresses o (positive if tensile, negative if compressive) and z (magnitude only) at this point on the inclined plane shown. Answers: MPa, t = MPa.

The stresses shown act at a point in a stressed body. Normal and shear stress magnitudes acting on horizontal and vertical planes at the point are Sy = 27 MPa, S, = 31 MPa, and Sy = 32 MPa. Assume ß = tan¬1 = 11.3°, a = 5, and b = 1. Using the equilibrium equation approach, determine the normal and shear stresses o (positive if tensile, negative if compressive) and z (magnitude only) at this point on the inclined plane shown. Answers: MPa, t = MPa.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter7: Analysis Of Stress And Strain

Section: Chapter Questions

Problem 7.3.10P: The normal and shear stresses acting on element B are ??x= -46 MPa, sy= -13 MPa, and txy= 21 MPa...

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Concept explainers

Stress transformation

The term stress indicates the measure of internal forces that develop due to an external force's application on an object. When a specific external force is applied to an object, internal stress generates in the material. The value of stress can obtain by taking the ratio of the externally applied force and cross-sectional area of the object. There are different types of stress depending on the type of external force.

Question

The stresses shown act at a point in a stressed body. Normal and shear stress magnitudes acting on horizontal and vertical planes at the point are S_x = 27 MPa, S_y = 31 MPa, and S_xy = 32 MPa. Assume β=tan−1(ba)=11.3∘β=tan-1(ba)=11.3∘, a = 5, and b = 1. Using the equilibrium equation approach, determine the normal and shear stresses σσ (positive if tensile, negative if compressive) and ττ (magnitude only) at this point on the inclined plane shown.

The stresses shown act at a point in a stressed body. Normal and shear stress magnitudes acting on horizontal and vertical planes at
= 11.3°, a = 5, and b = 1. Using the equilibrium
the point are Sy = 27 MPa, Sy = 31 MPa, and Syy = 32 MPa. Assume ß = tan¬!
equation approach, determine the normal and shear stresses o (positive if tensile, negative if compressive) and z (magnitude only) at
this point on the inclined plane shown.
|Sy
Sxy
Answers:
MPа.
MPa, t =

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