The stress concentration factor, K for a flat bar with a centric hole under axial loading is: 3 (27) + 3.66 (27) - 1.53 (²7) where: K= 3.00-3.13 r-radius of the hole, and D-the width of the bar, If D=75 mm, approximate the value of r to obtain K-3.5. (a) Determine your result using Bisection and Secant method. All data /values shall be in 4-decimal place. Do iteration up to five (5) iteration or stop if two consecutive r values are less than 0.001. (Hint: r is somewhere between 4 and 6 mm. Use this value as initial guess) (b) Discuss the differences of the answers from Q5(a).
The stress concentration factor, K for a flat bar with a centric hole under axial loading is: 3 (27) + 3.66 (27) - 1.53 (²7) where: K= 3.00-3.13 r-radius of the hole, and D-the width of the bar, If D=75 mm, approximate the value of r to obtain K-3.5. (a) Determine your result using Bisection and Secant method. All data /values shall be in 4-decimal place. Do iteration up to five (5) iteration or stop if two consecutive r values are less than 0.001. (Hint: r is somewhere between 4 and 6 mm. Use this value as initial guess) (b) Discuss the differences of the answers from Q5(a).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Q5 The stress concentration factor, K for a flat bar with a centric hole under axial loading is:
3
(²7) ² -
6 (27) -
1.53 (27)
K = 3.00-3.13
13 3 (27) + 3.66
where:
r=radius of the hole, and
D=
- the width of the bar,
If D=75 mm, approximate the value of r to obtain K = 3.5.
(a) Determine your result using Bisection and Secant method. All data /values shall be in
4-decimal place. Do iteration up to five (5) iteration or stop if two consecutiver values
are less than 0.001. (Hint: r is somewhere between 4 and 6 mm. Use this value as initial
guess)
(b)
Discuss the differences of the answers from Q5(a).
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