The stock concentration of potassium chromate is 3 mol/L. If you were to use 100 mL of the stock potassium chromatic solution, use the dilution equation to calculate how many mL of a 1 mol/L diluted solution you could make  b. How much water would you need to add to the 100 mL stock potassium chromate solution to create the 1 mol/L diluted solution ? How did you determine this value ?

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