The steady-state response of the system with transfer function H(s) = x(t) = 10 cos (40t +) + 5 cos (40t +) TT 01. y(t) = 20 cos (40t + 4 IT y(t) = 2 cos (40t + 4 O 4. None of the answers O 5. TT TT O2. y(t) = 10 cos (40t + + tan-¹) + 5 cos (40t + 4 3 03. - tan -1 4 + 10 cos (40t + tan-1 TT 3 3 -¹))+cos (40t +-tan-¹) + tan y(t) = 5 cos (40t +-tan-¹) + cos (40t +-tan an-¹) 10 to the input n-¹ (3) 3+0.1s
The steady-state response of the system with transfer function H(s) = x(t) = 10 cos (40t +) + 5 cos (40t +) TT 01. y(t) = 20 cos (40t + 4 IT y(t) = 2 cos (40t + 4 O 4. None of the answers O 5. TT TT O2. y(t) = 10 cos (40t + + tan-¹) + 5 cos (40t + 4 3 03. - tan -1 4 + 10 cos (40t + tan-1 TT 3 3 -¹))+cos (40t +-tan-¹) + tan y(t) = 5 cos (40t +-tan-¹) + cos (40t +-tan an-¹) 10 to the input n-¹ (3) 3+0.1s
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Question
Signalse and system

Transcribed Image Text:The steady-state response of the system with transfer function H(s) =
x(t) = 10 cos (40t + ) + 5 cos (40t +)
TT
01. y(t)= 20 cos (40t +
4
O2.
○ 3.
O 5.
IT
y(t) = 2 cos (40t +
4
O 4. None of the answers
- tan
TT
TT
y(t) = 10 cos (40t +
+ tan-¹)) + 5 cos (40t +
4
3
-1
4
+ 10 cos (40t +
tan-1
TT
3
3
-¹) + cos (40t +-tan-¹)
+ tan
y(t) = 5 cos (40t +-tan-¹) + cos (40t +-tan
an-¹)
2-¹))
10 to the input
n-¹ (3))
3+0.1s
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