The standard reduction potentials (E®) for the following half reactions are given. Oxaloacetate + 2H* + 2e malate E--0.166 V NAD* + 2H* + 2e NADH+ H E-0.320 V If you mixed oxaloacetate, malate, NAD, and NADH together, all at I M concentrations and in the presence of malate dehydrogenase, which of the following would happen initially? Oxaloacetate and malate would become oxidized; NAD* and NADH would become reduced. Malate would become oxidized, NAD would become reduced.

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Oxaloacetate and malate would become oxidized; NAD* and NADH would become
reduced.
Malate would become oxidized, NAD* would become reduced.
Oxaloacetate would become reduced, NADH would become oxidized.
No reaction would occur because all reactants and products are already at their
standard concentrations.
Transcribed Image Text:Oxaloacetate and malate would become oxidized; NAD* and NADH would become reduced. Malate would become oxidized, NAD* would become reduced. Oxaloacetate would become reduced, NADH would become oxidized. No reaction would occur because all reactants and products are already at their standard concentrations.
The standard reduction potentials (E®) for the following half reactions are given.
Oxaloacetate + 2H* + 2e
E --0.166 V
E =-0.320 V
malate
NAD* + 2H* + 20NADH + H*
If you mixed oxaloacetate, malate, NAD*, and NADH together, all at 1 M
concentrations and in the presence of malate dehydrogenase, which of the
following would happen initially?
Oxaloacetate and malate would become oxidized; NAD* and NADH would become
reduced.
Malate would become oxidized, NAD* would become reduced.
Transcribed Image Text:The standard reduction potentials (E®) for the following half reactions are given. Oxaloacetate + 2H* + 2e E --0.166 V E =-0.320 V malate NAD* + 2H* + 20NADH + H* If you mixed oxaloacetate, malate, NAD*, and NADH together, all at 1 M concentrations and in the presence of malate dehydrogenase, which of the following would happen initially? Oxaloacetate and malate would become oxidized; NAD* and NADH would become reduced. Malate would become oxidized, NAD* would become reduced.
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