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The standard form of the equation of a line going through (3, -3) and (0, 2) is: 5x - 3y + 6 = 0 Oy = - {x +2 %3D 3x + 5y -10 = 0 O 5x +3y -6= 0

The standard form of the equation of a line going through (3, -3) and (0, 2) is: 5x - 3y + 6 = 0 Oy = - {x +2 %3D 3x + 5y -10 = 0 O 5x +3y -6= 0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
The standard form of the equation of a line going through (3, -3) and (0, 2) is: 5x - 3y + 6 = 0 Oy = -x +2 3x + 5y -10 = 0 5x +3y -6= 0
Transcribed Image Text:The standard form of the equation of a line going through (3, -3) and (0, 2) is: 5x - 3y + 6 = 0 Oy = -x +2 3x + 5y -10 = 0 5x +3y -6= 0
(x² – 1, Given f(x) ={x+4, xS-1) -1<x<2} what is the value of f(0)? x 22 5, 4 O-1
Transcribed Image Text:(x² – 1, Given f(x) ={x+4, xS-1) -1<x<2} what is the value of f(0)? x 22 5, 4 O-1
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