The standard cell potential (E°cel) of the zinc-air battery is 1.65 V. If at 25.0°C the partial pressure of oxygen in the air diffusing through its cathode is 0.260 atm, what is the cell potential (Ece) ? Assume the cell reaction is: 2Zn(s) + O,(g) . → 2ZnO(s) The standard reduction potentials of the half-reactions in zinc-air batteries are: 0,(8) + 2H,0(1) + 4e → 40H (ag) E°rod = 0.401 V ZnO(s) +H,0(1) + 2e¯ → Zn(s)+20H¯(aq) E°r = - 1.25 V red 1st attempt See Periodic Table V
The standard cell potential (E°cel) of the zinc-air battery is 1.65 V. If at 25.0°C the partial pressure of oxygen in the air diffusing through its cathode is 0.260 atm, what is the cell potential (Ece) ? Assume the cell reaction is: 2Zn(s) + O,(g) . → 2ZnO(s) The standard reduction potentials of the half-reactions in zinc-air batteries are: 0,(8) + 2H,0(1) + 4e → 40H (ag) E°rod = 0.401 V ZnO(s) +H,0(1) + 2e¯ → Zn(s)+20H¯(aq) E°r = - 1.25 V red 1st attempt See Periodic Table V
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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
Transcribed Image Text:The standard cell potential (E°cel) of the zinc-air battery is 1.65 V. If at 25.0°C the partial pressure of oxygen in the air diffusing through its cathode is
0.260 atm, what is the cell potential (Ece) ? Assume the cell reaction is:
2Zn(s) + O,(g) .
→ 2ZnO(s)
The standard reduction potentials of the half-reactions in zinc-air batteries are:
0,(8) + 2H,0(1) + 4e
→ 40H (ag) E°rod = 0.401 V
ZnO(s) +H,0(1) + 2e¯ → Zn(s)+20H¯(aq) E°r
= - 1.25 V
red
1st attempt
See Periodic Table
V
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