**Problem Statement:**The speed of the incoming water is 25 cm/s, and the cross-sectional area of the hose carrying the water is 4.0 cm².**Problem:**1) Determine the time required for a 45-L container to be filled with water. *(Express your answer to two significant figures.)***Solution Approach:**To find the time required to fill the container, you need to calculate the flow rate of water through the hose and then determine how long it will take to reach a volume of 45 liters.- **Flow Rate Calculation:** - The flow rate (\( Q \)) is given by multiplying the speed of water (\( v \)) and the cross-sectional area (\( A \)) of the hose. - \( Q = v \times A = 25 \, \text{cm/s} \times 4.0 \, \text{cm}^2 = 100 \, \text{cm}^3/\text{s} \)- **Volume Conversion:** - Convert 45 liters to cubic centimeters because the flow rate is in cm³/s (1 L = 1000 cm³). - 45 L = 45,000 cm³- **Time Calculation:** - Time (\( t \)) required to fill the container is given by the total volume divided by the flow rate. - \( t = \frac{\text{Volume}}{\text{Flow Rate}} = \frac{45,000 \, \text{cm}^3}{100 \, \text{cm}^3/\text{s}} = 450 \, \text{s} \)Thus, the time required to fill the 45-L container is 450 seconds.

Name: **Problem Statement:**The speed of the incoming water is 25 cm/s, and
Uploaded: 2024-03-20T06:51:10.000Z
Channel: Bartleby
Description: **Problem Statement:**The speed of the incoming water is 25 cm/s, and the cross-sectional area of the hose carrying the water is 4.0 cm².**Problem:**1) Determine the time required for a 45-L container to be filled with water. *(Express your answer t