The speed of light in vacuum is 3 X 105 km/s and 1 km = 1,000 m and 1m = 100 cm. Use c = fA to determine the frequency of a photon with a wavelength of 2 cm.

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

1. The speed of light in vacuum is \(3 \times 10^5\) km/s and \(1 \text{ km} = 1,000 \text{ m}\) and \(1 \text{ m} = 100 \text{ cm}\). Use \(c = f \lambda\) to determine the frequency of a photon with a wavelength of 2 cm.

**Explanation of the Given Formula:**

- \(c\) represents the speed of light.
- \(f\) stands for frequency.
- \(\lambda\) (lambda) denotes wavelength.

This equation is used to relate the speed of light with frequency and wavelength, allowing us to solve for one variable if the others are known. 

**Conversion Factors:**

- Speed of light in meters per second: \(3 \times 10^5\) km/s = \(3 \times 10^8\) m/s. 
- Wavelength conversion: \(2 \text{ cm}\) = \(0.02 \text{ m}\).

**Solution Steps:**

To find frequency \(f\), rearrange the formula to:

\[ f = \frac{c}{\lambda} \]

Substitute the known values:

\[ f = \frac{3 \times 10^8 \text{ m/s}}{0.02 \text{ m}} \]

Calculate to find the frequency.

**Learning Objective:**

Understand how to use wave equations to calculate frequency, and practice unit conversions in the context of physics.
Transcribed Image Text:**Problem Statement:** 1. The speed of light in vacuum is \(3 \times 10^5\) km/s and \(1 \text{ km} = 1,000 \text{ m}\) and \(1 \text{ m} = 100 \text{ cm}\). Use \(c = f \lambda\) to determine the frequency of a photon with a wavelength of 2 cm. **Explanation of the Given Formula:** - \(c\) represents the speed of light. - \(f\) stands for frequency. - \(\lambda\) (lambda) denotes wavelength. This equation is used to relate the speed of light with frequency and wavelength, allowing us to solve for one variable if the others are known. **Conversion Factors:** - Speed of light in meters per second: \(3 \times 10^5\) km/s = \(3 \times 10^8\) m/s. - Wavelength conversion: \(2 \text{ cm}\) = \(0.02 \text{ m}\). **Solution Steps:** To find frequency \(f\), rearrange the formula to: \[ f = \frac{c}{\lambda} \] Substitute the known values: \[ f = \frac{3 \times 10^8 \text{ m/s}}{0.02 \text{ m}} \] Calculate to find the frequency. **Learning Objective:** Understand how to use wave equations to calculate frequency, and practice unit conversions in the context of physics.
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