The speed of light in vacuum is 3 X 105 km/s and 1 km = 1,000 m and 1m = 100 cm. Use c = fA to determine the frequency of a photon with a wavelength of 2 cm.
The speed of light in vacuum is 3 X 105 km/s and 1 km = 1,000 m and 1m = 100 cm. Use c = fA to determine the frequency of a photon with a wavelength of 2 cm.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
1. The speed of light in vacuum is \(3 \times 10^5\) km/s and \(1 \text{ km} = 1,000 \text{ m}\) and \(1 \text{ m} = 100 \text{ cm}\). Use \(c = f \lambda\) to determine the frequency of a photon with a wavelength of 2 cm.
**Explanation of the Given Formula:**
- \(c\) represents the speed of light.
- \(f\) stands for frequency.
- \(\lambda\) (lambda) denotes wavelength.
This equation is used to relate the speed of light with frequency and wavelength, allowing us to solve for one variable if the others are known.
**Conversion Factors:**
- Speed of light in meters per second: \(3 \times 10^5\) km/s = \(3 \times 10^8\) m/s.
- Wavelength conversion: \(2 \text{ cm}\) = \(0.02 \text{ m}\).
**Solution Steps:**
To find frequency \(f\), rearrange the formula to:
\[ f = \frac{c}{\lambda} \]
Substitute the known values:
\[ f = \frac{3 \times 10^8 \text{ m/s}}{0.02 \text{ m}} \]
Calculate to find the frequency.
**Learning Objective:**
Understand how to use wave equations to calculate frequency, and practice unit conversions in the context of physics.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5009a5f7-cb0c-44c8-a915-95d249ae3d2b%2Fd0dd5244-f934-4722-a09b-b5d217e220f4%2Fmeb2m5sq_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
1. The speed of light in vacuum is \(3 \times 10^5\) km/s and \(1 \text{ km} = 1,000 \text{ m}\) and \(1 \text{ m} = 100 \text{ cm}\). Use \(c = f \lambda\) to determine the frequency of a photon with a wavelength of 2 cm.
**Explanation of the Given Formula:**
- \(c\) represents the speed of light.
- \(f\) stands for frequency.
- \(\lambda\) (lambda) denotes wavelength.
This equation is used to relate the speed of light with frequency and wavelength, allowing us to solve for one variable if the others are known.
**Conversion Factors:**
- Speed of light in meters per second: \(3 \times 10^5\) km/s = \(3 \times 10^8\) m/s.
- Wavelength conversion: \(2 \text{ cm}\) = \(0.02 \text{ m}\).
**Solution Steps:**
To find frequency \(f\), rearrange the formula to:
\[ f = \frac{c}{\lambda} \]
Substitute the known values:
\[ f = \frac{3 \times 10^8 \text{ m/s}}{0.02 \text{ m}} \]
Calculate to find the frequency.
**Learning Objective:**
Understand how to use wave equations to calculate frequency, and practice unit conversions in the context of physics.
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