The speed of a car at time t, 5 ≤ ≤ 10, is given by f(t) = -2(t-10). The Mean Value Theorem guarantees that there will be a point in the interval [5, 10] when the instantaneous acceleration is equal to what number?
The speed of a car at time t, 5 ≤ ≤ 10, is given by f(t) = -2(t-10). The Mean Value Theorem guarantees that there will be a point in the interval [5, 10] when the instantaneous acceleration is equal to what number?
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I got an answer of -4 but it is wrong. I'm not sure if I have the wrong solution or if it's supposed to be positive 4. Plz help me
![The speed of a car at time \( t \), \( 5 \leq t \leq 10 \), is given by \( f(t) = -2(t-10)^2 \). The Mean Value Theorem guarantees that there will be a point in the interval \([5, 10]\) when the instantaneous acceleration is equal to what number?
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Transcribed Image Text:The speed of a car at time \( t \), \( 5 \leq t \leq 10 \), is given by \( f(t) = -2(t-10)^2 \). The Mean Value Theorem guarantees that there will be a point in the interval \([5, 10]\) when the instantaneous acceleration is equal to what number?
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