**Calculating Enantiomeric Excess (% ee)****Question:**The specific rotation of vitamin B₇ in water (at 22°C) is +92. A chemist prepared a mixture of vitamin B₇ and its enantiomer, and this mixture had a specific rotation of +12. Calculate the % ee of this mixture.**Answer:**To calculate the enantiomeric excess (% ee) of the mixture, use the following formula:% ee = \(\left( \frac{\text{observed specific rotation}}{\text{specific rotation of pure enantiomer}} \right) \times 100 \)Given:- Specific rotation of pure vitamin B₇ = +92- Specific rotation of the mixture = +12Substitute the values into the formula:% ee = \(\left( \frac{+12}{+92} \right) \times 100 \)% ee = 13.04Thus, the enantiomeric excess (% ee) of the mixture is 13.04%.**Interactive Element:**% ee = [ 13.04 ] %Note: The box above is an input field where users can enter their answer and check if it's correct.

Each enantiomer has its own optical rotation. Thus the enantiomer having more optical rotation will…

The specific rotation of vitamin B7 in water (at 22°C) is +92. A chemist prepared a mixture of vitamin B7 and its enantiomer, and this mixture had a specific rotation of +12. Calculate the % ee of this mixture. % ee = i

The specific rotation of vitamin B7 in water (at 22°C) is +92. A chemist prepared a mixture of vitamin B7 and its enantiomer, and this mixture had a specific rotation of +12. Calculate the % ee of this mixture. % ee = i

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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