The specific rotation of vitamin B7 in water (at 22°C) is +92. A chemist prepared a mixture of vitamin B7 and its enantiomer, and this mixture had a specific rotation of +12. Calculate the % ee of this mixture. % ee = i
The specific rotation of vitamin B7 in water (at 22°C) is +92. A chemist prepared a mixture of vitamin B7 and its enantiomer, and this mixture had a specific rotation of +12. Calculate the % ee of this mixture. % ee = i
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Calculating Enantiomeric Excess (% ee)**
**Question:**
The specific rotation of vitamin B₇ in water (at 22°C) is +92. A chemist prepared a mixture of vitamin B₇ and its enantiomer, and this mixture had a specific rotation of +12. Calculate the % ee of this mixture.
**Answer:**
To calculate the enantiomeric excess (% ee) of the mixture, use the following formula:
% ee = \(\left( \frac{\text{observed specific rotation}}{\text{specific rotation of pure enantiomer}} \right) \times 100 \)
Given:
- Specific rotation of pure vitamin B₇ = +92
- Specific rotation of the mixture = +12
Substitute the values into the formula:
% ee = \(\left( \frac{+12}{+92} \right) \times 100 \)
% ee = 13.04
Thus, the enantiomeric excess (% ee) of the mixture is 13.04%.
**Interactive Element:**
% ee = [ 13.04 ] %
Note: The box above is an input field where users can enter their answer and check if it's correct.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3cb00ede-af09-4713-a061-065b07b08661%2Fce4ac5c5-8e79-4871-ba0b-1b66e6d01203%2F0tcy22_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Calculating Enantiomeric Excess (% ee)**
**Question:**
The specific rotation of vitamin B₇ in water (at 22°C) is +92. A chemist prepared a mixture of vitamin B₇ and its enantiomer, and this mixture had a specific rotation of +12. Calculate the % ee of this mixture.
**Answer:**
To calculate the enantiomeric excess (% ee) of the mixture, use the following formula:
% ee = \(\left( \frac{\text{observed specific rotation}}{\text{specific rotation of pure enantiomer}} \right) \times 100 \)
Given:
- Specific rotation of pure vitamin B₇ = +92
- Specific rotation of the mixture = +12
Substitute the values into the formula:
% ee = \(\left( \frac{+12}{+92} \right) \times 100 \)
% ee = 13.04
Thus, the enantiomeric excess (% ee) of the mixture is 13.04%.
**Interactive Element:**
% ee = [ 13.04 ] %
Note: The box above is an input field where users can enter their answer and check if it's correct.
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