The specific rotation, [a]p, for (-)-2-butanol is +14.What is the observed rotation for a solution of 1.0 g of(-)-2-butanol in 10 mL of water in a sample tubehaving a pathlength of 10 cm?1.4 degrees .The observed rotation of a solution of 1.1 g of acompound in 10 mL of water is -10 degrees. If thepathlength is 10 cm, what is the specific rotation of thecompound? The specific rotation, [a]p, for sucrose is +67. What isthe observed rotation for a solution of 1.0 g of sucrosein 10 mL of water in a sample tube having a pathlengthof 10 cm?degrees .The observed rotation of a solution of 0.75 g of acompound in 10 mL of water is -2.4 degrees. If thepathlength is 10 cm, what is the specific rotation of thecompound?

Answered: The specific rotation, [a]p, for…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

The specific rotation, [a]p, for (-)-2-butanol is +14.
What is the observed rotation for a solution of 1.0 g of
(-)-2-butanol in 10 mL of water in a sample tube
having a pathlength of 10 cm?
1.4 degrees .
The observed rotation of a solution of 1.1 g of a
compound in 10 mL of water is -10 degrees. If the
pathlength is 10 cm, what is the specific rotation of the
compound?

The specific rotation, [a]p, for sucrose is +67. What is
the observed rotation for a solution of 1.0 g of sucrose
in 10 mL of water in a sample tube having a pathlength
of 10 cm?
degrees .
The observed rotation of a solution of 0.75 g of a
compound in 10 mL of water is -2.4 degrees. If the
pathlength is 10 cm, what is the specific rotation of the
compound?

Expert Solution

Step 1 Introduction interpretation

Basically there are two questions with two different images and according to guideline I have to solve only first image questions with both parts -

Interpretation-

1- To determine the observed rotation for a solution of 1g of (-)-2-butanol in 10 mL of water in sample tube having path length of 10 cm . The specific rotation of 2-butanol is 14.

2- To determine the specific rotation of the compound for a solution of 1.1 g of compound in 1mL of water when observed rotation of compound is -10 degree .

Concept-

To determine the specific rotation and observed rotation in a compound we use a formula that is -

${[α]}_{λ} = \frac{α}{C \times l}$

Where ${[α]}_{λ}$ - Specific rotation

$α$ - Observed rotation

C - Concertation of solution in ( g/mL)

l - Path length ( in dm )

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