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The specific growth rate of a yeast that produces an antibiotic is a function of the food concentration, c: 2c 4+0.8c+c²+0.2c³ g = As depicted in the given figure, growth goes to zero at very low concentrations due to food limitation. It also goes to zero at high concentrations due to toxicity effects. Find the value of cat which growth is a maximum. Calculate for 4 iterations of the Golden Section Search. Round your final value, Copt, to three decimal places. Start with your original boundaries at C=1 and C=3.

The specific growth rate of a yeast that produces an antibiotic is a function of the food concentration, c: 2c 4+0.8c+c²+0.2c³ g = As depicted in the given figure, growth goes to zero at very low concentrations due to food limitation. It also goes to zero at high concentrations due to toxicity effects. Find the value of cat which growth is a maximum. Calculate for 4 iterations of the Golden Section Search. Round your final value, Copt, to three decimal places. Start with your original boundaries at C=1 and C=3.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The specific growth rate of a yeast that produces an antibiotic is a function of the food concentration, c: 20 g 4+0.8c+c²+0.2c³ As depicted in the given figure, growth goes to zero at very low concentrations due to food limitation. It also goes to zero at high concentrations due to toxicity effects. Find the value of cat which growth is a maximum. Calculate for 4 iterations of the Golden Section Search. Round your final value, Copti to three decimal places. Start with your original bo ries at C=1 and C=3. 0.4 d-1) 0.2 5 10 c (mg/L)
Transcribed Image Text:The specific growth rate of a yeast that produces an antibiotic is a function of the food concentration, c: 20 g 4+0.8c+c²+0.2c³ As depicted in the given figure, growth goes to zero at very low concentrations due to food limitation. It also goes to zero at high concentrations due to toxicity effects. Find the value of cat which growth is a maximum. Calculate for 4 iterations of the Golden Section Search. Round your final value, Copti to three decimal places. Start with your original bo ries at C=1 and C=3. 0.4 d-1) 0.2 5 10 c (mg/L)
Remember that for the Golden Section Search; C2 = C, - d C, = C, + d d = (-1)(C,-C,) |
Transcribed Image Text:Remember that for the Golden Section Search; C2 = C, - d C, = C, + d d = (-1)(C,-C,) |
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