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The spacing of ruled lines or

The spacing of ruled lines or

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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m = 3 The spacing of ruled lines on a diffraction grating is 1830 rum. The grating is illuminated at normal incidence with a parallel beam of white light in the 400 nm to 700 nm wavelength band. The second order spectrum and the third order spectrum overlap. The angular width of the overlap is closest to: m = 2 A) 6.9° B) 8.9° C) 4.9* D) 5.9 1830mm 1830 λ = 400am-700mm..! m=2 & m = 3 overlap Sing, = ma d smallest ↓ › ↓ d₂ton = X Spois Sino₂-sin, = (3-2) biggest d 22.489-12.6 The pupil of a cat's eye narrows to a slit of width 0.5 mm in daylight. Assuming a wavelength 10 m) of 500 nm, what is the angular resolution? (1 nm = 500 x 10 distance between -9 1-3m E) 7.9 1 1830×10-9
Transcribed Image Text:m = 3 The spacing of ruled lines on a diffraction grating is 1830 rum. The grating is illuminated at normal incidence with a parallel beam of white light in the 400 nm to 700 nm wavelength band. The second order spectrum and the third order spectrum overlap. The angular width of the overlap is closest to: m = 2 A) 6.9° B) 8.9° C) 4.9* D) 5.9 1830mm 1830 λ = 400am-700mm..! m=2 & m = 3 overlap Sing, = ma d smallest ↓ › ↓ d₂ton = X Spois Sino₂-sin, = (3-2) biggest d 22.489-12.6 The pupil of a cat's eye narrows to a slit of width 0.5 mm in daylight. Assuming a wavelength 10 m) of 500 nm, what is the angular resolution? (1 nm = 500 x 10 distance between -9 1-3m E) 7.9 1 1830×10-9
Expert Solution
Step 1

distance between the ruled lines = d = 1838 nm

wavelengths = 400 nm and 700 nm

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