The space between the plates of a parallel-plate capacitor is filled with two slabs of dielectric material. Each slab has thickness a/2, so the total distance between the plates a. Slab I has a polarization of P, = k,9, and slab II has polarization of P, = k2y –59. The capacitor has square plates Q1. of side length b and uniform charge density of o. Express your answers in terms of given quantities. a) Find the surface and volume bound charge densities for slab I and slab 2. b) Find total bound charge. c) Find the electric displacement vector D in slab I and slab Slab Slab a/2
The space between the plates of a parallel-plate capacitor is filled with two slabs of dielectric material. Each slab has thickness a/2, so the total distance between the plates a. Slab I has a polarization of P, = k,9, and slab II has polarization of P, = k2y –59. The capacitor has square plates Q1. of side length b and uniform charge density of o. Express your answers in terms of given quantities. a) Find the surface and volume bound charge densities for slab I and slab 2. b) Find total bound charge. c) Find the electric displacement vector D in slab I and slab Slab Slab a/2
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Transcribed Image Text:Q1.1
The space between the plates of a parallel-plate capacitor is filled with two slabs of
dielectric material. Each slab has thickness a/2, so the total distance between the plates a. Slab I has a
polarization of P, = k,9, and slab II has polarization of P, = k2(y –59. The capacitor has square plates
of side length b and uniform charge density of o. Express
your answers in terms of given quantities.
+o
b
a) Find the surface and volume bound charge densities for
slab I and slab 2.
b) Find total bound charge.
c) Find the electric displacement vector Ď in slab I and slab
II.
d) Find the electric field vector E in slab I and slab II.
e) Find the potential difference between the plates
f) Find the capacitance of the capacitor.
Slab 1
b
Slab 2
a/2
a/2
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