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The solutions of cosh(2x) = 8sinhx - 5 are a) x = ln (4+ √17) and x = ln (1 + in (1 + √2) b) x = ln (3+√10) and x 10) and x = ln (1 + √2) Odx = In (3+√10) and x = ln (5+ √26 c) X ln ○d) x = ln (2 + √5) and x = ln (1 + √2)

The solutions of cosh(2x) = 8sinhx - 5 are a) x = ln (4+ √17) and x = ln (1 + in (1 + √2) b) x = ln (3+√10) and x 10) and x = ln (1 + √2) Odx = In (3+√10) and x = ln (5+ √26 c) X ln ○d) x = ln (2 + √5) and x = ln (1 + √2)

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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The solutions of cosh(2x) = 8sinhx - 5 are a) x = ln (4 + √17) and x = ln (1 + √2) b) x = x = ln (3+√10) and x = In (1 + √2) c) x = ln (3+√10) and x = ln (5+ √26 X d) x = ln (2 + √5) and x = ln (1 + v
Transcribed Image Text:The solutions of cosh(2x) = 8sinhx - 5 are a) x = ln (4 + √17) and x = ln (1 + √2) b) x = x = ln (3+√10) and x = In (1 + √2) c) x = ln (3+√10) and x = ln (5+ √26 X d) x = ln (2 + √5) and x = ln (1 + v
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