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The solution to the problem. =b, max f(x, X2. Xg)=x, + Xg subject to for b, =1 and by =2 is (k,X)=2, -2. 2.047 (Put /2 1.4.) In 2), with associated Lagrange multipliers 2, - 1214 and ,- 1/2. What is the approximate change Af in the optimal value of fif b, is increased to 1.04 and b, is increased to O A. 0.08 OB. 1.2 OC. 0.85 OD. 0.034

The solution to the problem. =b, max f(x, X2. Xg)=x, + Xg subject to for b, =1 and by =2 is (k,X)=2, -2. 2.047 (Put /2 1.4.) In 2), with associated Lagrange multipliers 2, - 1214 and ,- 1/2. What is the approximate change Af in the optimal value of fif b, is increased to 1.04 and b, is increased to O A. 0.08 OB. 1.2 OC. 0.85 OD. 0.034

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The solution to the problem. = b1 max f(x1, X2. X3) = X, + X3 subject to x, +x, + = by for b = 1 and b2 = 2 is (X1,X2,X3) = (2, -12, In 2), with associated Lagrange multipliers = 2/4 and 2 = 1/2. What is the approximate change Af * in the optimal value of fif b, is increased to 1.04 and b, is increased to %3D 2.04? (Put 2 1.4.) ..... O A. 0.08 OB. 1.2 O C. 0.85 O D. 0.034
Transcribed Image Text:The solution to the problem. = b1 max f(x1, X2. X3) = X, + X3 subject to x, +x, + = by for b = 1 and b2 = 2 is (X1,X2,X3) = (2, -12, In 2), with associated Lagrange multipliers = 2/4 and 2 = 1/2. What is the approximate change Af * in the optimal value of fif b, is increased to 1.04 and b, is increased to %3D 2.04? (Put 2 1.4.) ..... O A. 0.08 OB. 1.2 O C. 0.85 O D. 0.034
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