The solution to the differential equation: v² (x +sin*5x) – 3y] dx + (yx² – 3x +xy – 5 + 6y -ysin10x) dy = 0 when x = 0, y = - 1 may be expressed in the form x*ye +;xyª -ysin(cx) + dxy + eyª + fy = ab Find: a + b + c +d+e+ f.

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A: This question is from linear partial differential equation.

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A: First order ordinary differential equation.

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A: Given solution, y=c1cos3x+c2sin3x So, y'=-3c1sin3x+3c2cos3x So, y"= -9c1cos3x -9c2sin3x

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