The solution of the initial value problem y' = 3 – 2y, y(-1) = 2, is o(t). Then lim ø(t) = 3/2. t (s) An integrating factor for t'y' + 24 = sin t, t> 0, is t'/2.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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(r)
The solution of the initial value problem y' = 3 – 2y, y(-1) = 2, is ø(t).
||
Then lim ø(t) = 3/2.
t
(s)
An integrating factor for t'y' +y =
sin t, t> 0, is t'/2.
2°
Transcribed Image Text:(r) The solution of the initial value problem y' = 3 – 2y, y(-1) = 2, is ø(t). || Then lim ø(t) = 3/2. t (s) An integrating factor for t'y' +y = sin t, t> 0, is t'/2. 2°
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