The solution of the following separable differential equation (y − 4) 4 = (x – cosx)(y +1) is: " }ln(y2 + 1) – 4tan-Ây = -cosx+c b. ln(y² + 1) -4tan ¹y = - sinx + c c. In (y² + 1) - 4sin-¹y = d. None of the - sinx + c

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The solution of the following separable differential equation
(y − 4) Y = (x − cosx)(y +1)
is:
"
a. }In(y2 + 1) – 4tan-ly = -cosx to
b.
ln(y² + 1) — 4tan-¹y = 2-sinx + c
c.
In (y² + 1) - 4sin-¹y = - sinx + c
None of them
d.
Xiaren
Transcribed Image Text:The solution of the following separable differential equation (y − 4) Y = (x − cosx)(y +1) is: " a. }In(y2 + 1) – 4tan-ly = -cosx to b. ln(y² + 1) — 4tan-¹y = 2-sinx + c c. In (y² + 1) - 4sin-¹y = - sinx + c None of them d. Xiaren
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