The solution of the first order ODE defined by ełydy=(y+1) (e*+1) dx yln(ly+1|) =xeX+c, where c is a constant. y+ in (ly+1|) =x+e*+c, where c is a constant. An(ly+1|| =x -e*+c, where c is a constant. (y=In(y+1) – xe² +c, where c is a constant.
The solution of the first order ODE defined by ełydy=(y+1) (e*+1) dx yln(ly+1|) =xeX+c, where c is a constant. y+ in (ly+1|) =x+e*+c, where c is a constant. An(ly+1|| =x -e*+c, where c is a constant. (y=In(y+1) – xe² +c, where c is a constant.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![The solution of the first order ODE def ined by ełydy=(y+1) (e*+1)dx
yln(]y+1|) =xe*+c, where c is a constant.
y+ In(|y+1|) =x+e* +c, where c is a constant.
In(y+1) =x – ex+c, where c is a constant.
Da(ly+1) -
(y=n(|y+1|) – xe* +c, where c is a constant.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fabf9a6d6-e79e-4fb4-aebc-ad4c20ac03c2%2Fbc3f8a7b-e350-47f5-ad1f-eb448c65d975%2F94f0gab_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The solution of the first order ODE def ined by ełydy=(y+1) (e*+1)dx
yln(]y+1|) =xe*+c, where c is a constant.
y+ In(|y+1|) =x+e* +c, where c is a constant.
In(y+1) =x – ex+c, where c is a constant.
Da(ly+1) -
(y=n(|y+1|) – xe* +c, where c is a constant.
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