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The solution of the differential equation xy" – 3xy' + 4y = 0 is O ye = Cjx + c2x² O ye = C1x + c2x³3 O ye = C1x + c2x In x O ye = C1x? + c2x² In x

The solution of the differential equation xy" – 3xy' + 4y = 0 is O ye = Cjx + c2x² O ye = C1x + c2x³3 O ye = C1x + c2x In x O ye = C1x? + c2x² In x

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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2) Please help with following multiple choice.

The following multiple-choice question is presented regarding the solution of a specific differential equation: The solution of the differential equation \(x^2 y'' - 3x y' + 4y = 0\) is: - \(y_c = c_1 x + c_2 x^2\) - \(y_c = c_1 x + c_2 x^3\) - \(y_c = c_1 x + c_2 x \ln x\) - \(y_c = c_1 x^2 + c_2 x^2 \ln x\) Here, \(c_1\) and \(c_2\) are constants of integration.
Transcribed Image Text:The following multiple-choice question is presented regarding the solution of a specific differential equation: The solution of the differential equation \(x^2 y'' - 3x y' + 4y = 0\) is: - \(y_c = c_1 x + c_2 x^2\) - \(y_c = c_1 x + c_2 x^3\) - \(y_c = c_1 x + c_2 x \ln x\) - \(y_c = c_1 x^2 + c_2 x^2 \ln x\) Here, \(c_1\) and \(c_2\) are constants of integration.
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