The solution is done. But can you answer this question based on the solution? Question: How did I get the new elements in the matrices?
The solution is done. But can you answer this question based on the solution? Question: How did I get the new elements in the matrices?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The solution is done. But can you answer this question based on the solution?
Question: How did I get the new elements in the matrices?

Transcribed Image Text:Son
for forst îtoration of phase
2
Min Z- Bn, + 212 t
frost itention for phase
2.
2
S3
RHS
CB
Basic
3.25
6. 25
O'S
-0.25
-0:25
2.5
0- 75
2.5-
-235
- 125
ond
Since
in z1-i 12÷ 0.S is enteu the bas's
S3 depant the basis
e 2nd
1tena tion
foo Phase 2.
2
CB
B-b
3.1
-0.2
6
-0.4
-0'2
6.3
03
O.4
1
2
-0:2
ー24
Since
all
optimal Solution
arwured
with
![Question 4
Consider the following tableau:
Cj
000
Ci Basis x1 x2 x3
s1 s2
s3 R1
RHS
00.5 3.25 10.25 0 -0.25 6.5
1 0.5-0.25 0 -0.25 0 0.25 1.5
0 2.5 0.75 0 0.75 1 -0.75 2.5
0 s1
0 x1
0 s3
Zi-Cj 0 0 0
Use this information for the first iteration of phase 2, considering the following OF:
Min Z = 5x1+2x2+x3
%3D
Complete the table for the SECOND iteration pf phase 2
Cj
Cj Basis x1
[C1] [C2] [C3] (C4] [C5] [C6]
s3
x2
x3
s1
s2
RHS Theta
[c1] [b1] [x11] [x12] [x13] [x14] [x15] [x16] [r1] [t1]
[c2] [b2]x21] [x22] [x23] [x24] [x25] [x26] [r2] [t2]
[c3] [b3] [x31] [x32] [x33] [x34] [x35] [x36] [r3] [t3]
[21] 22] 23] 24] 25] 26] zs]
Zi-Cj[zc1] [zc2] [zc3] [zc4] [zc5] [zc6]
Fill any N/A values with '0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32b11b45-8156-47f3-9cde-488b1bb837a5%2Fb611c1f8-a14a-49ff-b065-8f0e4ae5e6fd%2Fybvjx2d_processed.png&w=3840&q=75)
Transcribed Image Text:Question 4
Consider the following tableau:
Cj
000
Ci Basis x1 x2 x3
s1 s2
s3 R1
RHS
00.5 3.25 10.25 0 -0.25 6.5
1 0.5-0.25 0 -0.25 0 0.25 1.5
0 2.5 0.75 0 0.75 1 -0.75 2.5
0 s1
0 x1
0 s3
Zi-Cj 0 0 0
Use this information for the first iteration of phase 2, considering the following OF:
Min Z = 5x1+2x2+x3
%3D
Complete the table for the SECOND iteration pf phase 2
Cj
Cj Basis x1
[C1] [C2] [C3] (C4] [C5] [C6]
s3
x2
x3
s1
s2
RHS Theta
[c1] [b1] [x11] [x12] [x13] [x14] [x15] [x16] [r1] [t1]
[c2] [b2]x21] [x22] [x23] [x24] [x25] [x26] [r2] [t2]
[c3] [b3] [x31] [x32] [x33] [x34] [x35] [x36] [r3] [t3]
[21] 22] 23] 24] 25] 26] zs]
Zi-Cj[zc1] [zc2] [zc3] [zc4] [zc5] [zc6]
Fill any N/A values with '0
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