The solution is done. But can you answer this question based on the solution?  Question: How did I  get the new elements in the matrices?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The solution is done. But can you answer this question based on the solution? 

Question: How did I  get the new elements in the matrices?

Son
for forst îtoration of phase
2
Min Z- Bn, + 212 t
frost itention for phase
2.
2
S3
RHS
CB
Basic
3.25
6. 25
O'S
-0.25
-0:25
2.5
0- 75
2.5-
-235
- 125
ond
Since
in z1-i 12÷ 0.S is enteu the bas's
S3 depant the basis
e 2nd
1tena tion
foo Phase 2.
2
CB
B-b
3.1
-0.2
6
-0.4
-0'2
6.3
03
O.4
1
2
-0:2
ー24
Since
all
optimal Solution
arwured
with
Transcribed Image Text:Son for forst îtoration of phase 2 Min Z- Bn, + 212 t frost itention for phase 2. 2 S3 RHS CB Basic 3.25 6. 25 O'S -0.25 -0:25 2.5 0- 75 2.5- -235 - 125 ond Since in z1-i 12÷ 0.S is enteu the bas's S3 depant the basis e 2nd 1tena tion foo Phase 2. 2 CB B-b 3.1 -0.2 6 -0.4 -0'2 6.3 03 O.4 1 2 -0:2 ー24 Since all optimal Solution arwured with
Question 4
Consider the following tableau:
Cj
000
Ci Basis x1 x2 x3
s1 s2
s3 R1
RHS
00.5 3.25 10.25 0 -0.25 6.5
1 0.5-0.25 0 -0.25 0 0.25 1.5
0 2.5 0.75 0 0.75 1 -0.75 2.5
0 s1
0 x1
0 s3
Zi-Cj 0 0 0
Use this information for the first iteration of phase 2, considering the following OF:
Min Z = 5x1+2x2+x3
%3D
Complete the table for the SECOND iteration pf phase 2
Cj
Cj Basis x1
[C1] [C2] [C3] (C4] [C5] [C6]
s3
x2
x3
s1
s2
RHS Theta
[c1] [b1] [x11] [x12] [x13] [x14] [x15] [x16] [r1] [t1]
[c2] [b2]x21] [x22] [x23] [x24] [x25] [x26] [r2] [t2]
[c3] [b3] [x31] [x32] [x33] [x34] [x35] [x36] [r3] [t3]
[21] 22] 23] 24] 25] 26] zs]
Zi-Cj[zc1] [zc2] [zc3] [zc4] [zc5] [zc6]
Fill any N/A values with '0
Transcribed Image Text:Question 4 Consider the following tableau: Cj 000 Ci Basis x1 x2 x3 s1 s2 s3 R1 RHS 00.5 3.25 10.25 0 -0.25 6.5 1 0.5-0.25 0 -0.25 0 0.25 1.5 0 2.5 0.75 0 0.75 1 -0.75 2.5 0 s1 0 x1 0 s3 Zi-Cj 0 0 0 Use this information for the first iteration of phase 2, considering the following OF: Min Z = 5x1+2x2+x3 %3D Complete the table for the SECOND iteration pf phase 2 Cj Cj Basis x1 [C1] [C2] [C3] (C4] [C5] [C6] s3 x2 x3 s1 s2 RHS Theta [c1] [b1] [x11] [x12] [x13] [x14] [x15] [x16] [r1] [t1] [c2] [b2]x21] [x22] [x23] [x24] [x25] [x26] [r2] [t2] [c3] [b3] [x31] [x32] [x33] [x34] [x35] [x36] [r3] [t3] [21] 22] 23] 24] 25] 26] zs] Zi-Cj[zc1] [zc2] [zc3] [zc4] [zc5] [zc6] Fill any N/A values with '0
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