The solubility of Cr(NO3)3 . 9 H2O in water is 208 g per 100 gof water at 15 °C. A solution of Cr(NO3)3 # 9 H2O in water at35 °C is formed by dissolving 324 g in 100 g of water. Whenthis solution is slowly cooled to 15 °C, no precipitate forms.(a) Is the solution that has cooled down to 15 °C unsaturated,saturated, or supersaturated? (b) You take a metal spatulaand scratch the side of the glass vessel that contains thiscooled solution, and crystals start to appear. What has justhappened? (c) At equilibrium, what mass of crystals do youexpect to form?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The solubility of Cr(NO3)3 . 9 H2O in water is 208 g per 100 g
of water at 15 °C. A solution of Cr(NO3)3 # 9 H2O in water at
35 °C is formed by dissolving 324 g in 100 g of water. When
this solution is slowly cooled to 15 °C, no precipitate forms.
(a) Is the solution that has cooled down to 15 °C unsaturated,
saturated, or supersaturated? (b) You take a metal spatula
and scratch the side of the glass vessel that contains this
cooled solution, and crystals start to appear. What has just
happened? (c) At equilibrium, what mass of crystals do you
expect to form?

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