The solid frame is subjected to the forces shown, calculate the distance (d) if * the moment at A equal (MA=-11 N.m) (clockwise + and counter clockwise -) 50N 45° 2m Im 40N 27 kN 3m 30 d3? 2m 100N 6m 6m

5b. If lengths a=1.1m, b=4.8m, c=1.1m, d=3.2m, e=1.3m, and f=3.2m, determine the moment (in N*m) caused by force F_A about axis OD. Answer must include 1 place after the decimal point. Negative sign must be included if the rotational tendency about the OD axis (from O to D) is clockwise.

SOLVE FOR THE SUM OF MOMENT OF ALL FORCES CLOCKWISE DIRECTION IS POSITIVE AT POINT A, B, C AND D. Nool =4 G= 80N 2m 2m R= 90N 2m P= 120N 2m 2m 2m

GO 321 3 in F1 F2 a F3 A d F4 F5 Consider the following values: - a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 7 kN; F2 = 8 kN; F3 = 9 kN; F4 = 10 kN; F5 = 11 kN; a = 30°, 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 158 kN.m b) 127 kN.m c) 146 kN.m d) - 103 kN.m e) 241 kN.m f) - 171 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 98.8 kN.m b) - 291.7 kN.m c) 311.6 kN.m d) – 264.6 kN.m e) 354.2 kN.m f) - 242.5 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m b) - 141.1 kN.m c) 14.6 kN.m d) - 272.1 kN.m e) 174.1 kN.m f) - 315.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 117.8 kN.m b) 82.7 kN.m c) 121.9 kN.m d) - 259.9 kN.m e) 127.1 kN.m f) 300.1 kN.m Activate 5] What is the moment of the force F2 about point E? a) 151.7 kN.m b) 118.1 kN.m c) 214.6 kN.m d) 158.6 kN.m e) 101.1 kN.m lo