The soil profile shown carries a uniformly distributed load of 75 kPa applied at the ground surface. Use Cs = 1/5 Cc. Determine the settlement of the clay layer due to primary consolidation considering the following cases: a. The clay is normally consolidated (0.242m) b. If Pc = 205 kPa (0.0484m) c. If OCR = 1.6219 (0.0764m) 75 kN/m2 2.4 m SAND ydry 14.75kN/m .GWT 4.6 m SAND ysat =17.45KN/m³ ysat = 20.62 kN/m³ e=0.9 LL - 50 5,2 m CLAY

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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The answer should be

A. 0.242m

B. 0.0484m

C. 0.0764 m

The soil profile shown carries a uniformly distributed load of 75 kPa applied at the ground
surface. Use Cs = 1/5 Cc.
Determine the settlement of the clay layer due to primary consolidation considering the
following cases:
a. The clay is normally consolidated (0.242m)
b. If Pc = 205 kPa (0.0484m)
If OCR = 1.6219 (0.0764m)
C.
75 kN/m
2.4 m
SAND
ydry 14.75kN/m
V GWT
4.6 m
SAND
ysat 17.45KN/m
ysat = 20.62 kN/m³
e =0.9
LL - 50
5,2m
CLAY
SETTLEMENT DUE TO SECONDARY CONSOLIDATION
Ss = C'a H log )
Eq. 14
Ca
1 + ep
Ae
C'a =
Eq. 15
Ca =
Eq. 16
log ()
where:
Ss = secondary consolidation settlement
Ca = secondary compression index
e, = void ratio at the end of primary consolidation
= e,-Ae
H = thickness of clay layer
t1, t2 = time
Transcribed Image Text:The soil profile shown carries a uniformly distributed load of 75 kPa applied at the ground surface. Use Cs = 1/5 Cc. Determine the settlement of the clay layer due to primary consolidation considering the following cases: a. The clay is normally consolidated (0.242m) b. If Pc = 205 kPa (0.0484m) If OCR = 1.6219 (0.0764m) C. 75 kN/m 2.4 m SAND ydry 14.75kN/m V GWT 4.6 m SAND ysat 17.45KN/m ysat = 20.62 kN/m³ e =0.9 LL - 50 5,2m CLAY SETTLEMENT DUE TO SECONDARY CONSOLIDATION Ss = C'a H log ) Eq. 14 Ca 1 + ep Ae C'a = Eq. 15 Ca = Eq. 16 log () where: Ss = secondary consolidation settlement Ca = secondary compression index e, = void ratio at the end of primary consolidation = e,-Ae H = thickness of clay layer t1, t2 = time
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