The smooth hollow tube assembly rotates about a vertical axis with angular velocity @ = 0 = 3.5 rad/s and = 0 = -2.6 rad/s².Asmall 0.26-kg slider P moves inside the horizontal tube portion under the control of the string which passes out the bottom of theassembly. If r = 1.12 m, r = -2.0 m/s, and * = 4.9 m/s2, determine the tension T in the string and the horizontal force Fe exerted onthe slider by the tube. T is positive in tension, and Fe is positive if in the positive direction.TNNAnswers:T =Fe=ii

ω=θ˙=3.5rad/sω˙=θ¨=-2.6rad/s2m=0.26-kgr=1.12mr˙=-2.0m/sr¨=4.9m/s2 To-Find:- T=____NFθ=____N

The smooth hollow tube assembly rotates about a vertical axis with angular velocity @ = 0 = 3.5 rad/s and = 0 = -2.6 rad/s². A mall 0.26-kg slider P moves inside the horizontal tube portion under the control of the string which passes out the bottom of the ssembly. If r = 1.12 m, r = -2.0 m/s, and * = 4.9 m/s², determine the tension T in the string and the horizontal force Fe exerted on he slider by the tube. T is positive in tension, and Fe is positive if in the positive direction. dre

The smooth hollow tube assembly rotates about a vertical axis with angular velocity @ = 0 = 3.5 rad/s and = 0 = -2.6 rad/s². A mall 0.26-kg slider P moves inside the horizontal tube portion under the control of the string which passes out the bottom of the ssembly. If r = 1.12 m, r = -2.0 m/s, and * = 4.9 m/s², determine the tension T in the string and the horizontal force Fe exerted on he slider by the tube. T is positive in tension, and Fe is positive if in the positive direction. dre

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

See Image
N L400mm- 300 mm P=10 rad/s find acceleration at point a on rim of the wheel. 4rad/s = ta
For the circular thin plate with a square hole as shown in the image below, its radius R = 0.32 m and the side of the square /= 0.18 m, and the material has a mass per unit area of 12 kg/m². If at the instant shown, it is subjected to a force P = 30 N, and has a counterclockwise angular velocity of W = 4.2 rad/s, determine magnitude of the support reaction at point O at this instant. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper unit. Take g = 9.81 m/s². R @ Your Answer: Answer units P
Rod OA rotates counterclockwise at a constant angular rate 0-4 rad/s. The double collar B is pin-connected together such that one collar slides over the rotating rod and the other collar slides over the circular rod described by the equation r= (1.6 cos 6) m. Both collars have a mass of 0.65 kg. Motion is in the vertical plane. (Figure 1) Figure r=1.6 cos 9. 0-4 rad/s 0.8 m 1 of 1 Part A Determine the magnitude of the force which the circular rod exerts on one of the collars at the instant 0=45 Express your answer to three significant figures and include the appropriate units. ▸ View Available Hint(s) F= Value Submit μÁ Part B Previous Answers Units X Incorrect; Try Again; 5 attempts remaining Determine the magnitude of the force that OA exerts on the other colar at the instant @-45. Express your answer to three significant figures and include the appropriate units. View Available Hint(s)
Rod AB is fixed to move horizontally, with end A moving the constant velocity shown in the figure. What is the vertical speed of mass m when the angle 0 is 60 degrees? v = 10 m/s D 300 mm 300 mm
A "swing ride" is shown in the figure. Calculate the necessary angular velocity w for the swings to assume an angle 0 = 44° with the vertical. Neglect the mass of the cables and treat the chair and person as one particle. Assume r = 4.1 m, L = 6.0 m. Answer: W= i rad/s
Please answer all
The handcart has a mass of 215 kg and center of mass at G. A force P=1075 N that is applied to the handle to push the handcart along a rough horizontal surface (u-0.2). Neglect the mass of the wheels. tan(0)=4/3 0.5 m 0.2 m -0.3 m--0.2 m-- 0.4 m The handle cart acceleration (m/s) O a. 0.432 b. 0.24 O C.0.336 O d. 0.384 O e. 0.192
Consider a toy vehicle with a body of mass M = 2Kg on two wheels, each of mass m = 1Kg and radius r = 0.1 m as shown in the figure. It starts from rest on top of a small hill of height H = 10 m and rolls without slipping. What is the linear velocity of the center of mass at the bottom of the hill? HINT: There is rotational and translational kinetic energy in this problem. Vo = 0 M- Vf M-2K m=lKg molky
A ball governor of the vertical compression spring type runs at a mean speed of N = 189.228 rev/min. The bell crank lever arms are a = 0.158 m and b = 0.063 m and the rotating balls have a mass of m = 2.793 kg each, and the ball radius is r = 0.114 m at the mean speed. Part A: If the speed range of the governor at the mean speed is A = 1.287 rev/min, determine the friction force Fu at the sleeve (neglect the effect of gravity on the balls). Part B: Determine the spring stiffness S that would be required to make the governor isochronous if the sleeve lift is y = 0.013 m from the mean position (assume the ball arm is vertical at the mean position).
Attached to the rope of length R = 0.5m, the object with mass m = 1kg is rotated clockwise in a vertical plane. Object; The linear speed is 2m / s when it is at point A in the first second, and when the linear speed is 8m / s when it is at point B in the second second, the theta = 127 degrees between A and B is swept. a) Calculate the tensile forces on the rope while the object is at A and B points. b) Calculate the total acceleration vectorially when the object is at point A. (g=10m/s^2, sin37=0.6 and cos37=0.8)
The 10 N cylinder moves in a frictionless pipe. Spring constants are k1 = 150 N / m and k2 = 200 N / m. When the system is at rest, d = 0.5 m. (d is the distance from the right end of the arc k2). The system rotates around a fixed z-axis. Find the constant velocity of the cylinder for d = 0.20 m?