The smooth bar rotates in the horizontal plane with constant angular velocity wn = 4 rad/s. If the radial velocity of the 1-kg collar Ais v, = 3 m/s when its radial position is r = 1.5 m. Applying the Newton's 2nd law. find two correct answers from the following: 3m O The magnitude of the heads velocity at the radial distance $r is given by sgrt( 32 ^2 - 27) m/s. O Radial acceleration a, = # – 16r = -g sin 0. The radial component of the acceleration is equal to zero. O The equation of motion for the collar perpendicular to the bar is given by N – gcos 0 = ag. %3D O The total acceleration of the collar is zero. 4/7

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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The smooth bar rotates in the horizontal plane with constant angular velocity wn = 4 rad/s. If the radial velocity of the
1-kg collar A is v, = 3 m/s when its radial position is r= 1.5 m. Applying the Newton's 2nd law. find two correct
answers from the following:
O The magnitude of the heads velocity at the radial distance $r is given by sqrt( 32 ^2 - 27) m/s.
O Radial acceleration a, = # – 16r = -gsin 0.
O The radial component of the acceleration is equal to zero.
O The equation of motion for the collar perpendicular to the bar is given by N – g cos 0 = ag.
O The total acceleration of the collar is zero.
4/7
Transcribed Image Text:The smooth bar rotates in the horizontal plane with constant angular velocity wn = 4 rad/s. If the radial velocity of the 1-kg collar A is v, = 3 m/s when its radial position is r= 1.5 m. Applying the Newton's 2nd law. find two correct answers from the following: O The magnitude of the heads velocity at the radial distance $r is given by sqrt( 32 ^2 - 27) m/s. O Radial acceleration a, = # – 16r = -gsin 0. O The radial component of the acceleration is equal to zero. O The equation of motion for the collar perpendicular to the bar is given by N – g cos 0 = ag. O The total acceleration of the collar is zero. 4/7
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