The slope of a line that is parallel to 5x – y = 7 is m = The equation of the line (in slope-intercept form) parallel to 5x – Y = 7 that passes through the point ( – 3, – 2) is Y =

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Question
### Finding the Slope and Equation of Parallel Lines

**Finding the Slope**

To determine the slope of a line that is parallel to the given line equation:
\[ 5x - y = 7 \]

First, convert the equation into slope-intercept form (\( y = mx + b \)):

\[ 5x - y = 7 \]
\[ -y = -5x + 7 \]
\[ y = 5x - 7 \]

From this, we can see that the slope (\( m \)) of the line is 5.

\[ m = \boxed{5} \]

**Finding the Equation of the Parallel Line**

Next, to find the equation of a line in slope-intercept form that is parallel to \( 5x - y = 7 \) and passes through the point \( (-3, -2) \):

1. We know the slope (\( m \)) is the same: 5.
2. Substitute the slope (\( m = 5 \)) and the given point \( (x_1, y_1) = (-3, -2) \) into the point-slope form of the line equation: 
   \[ y - y_1 = m(x - x_1) \]

\[ y - (-2) = 5(x - (-3)) \]
\[ y + 2 = 5(x + 3) \]
\[ y + 2 = 5x + 15 \]
\[ y = 5x + 13 \]

Hence, the equation of the line parallel to \( 5x - y = 7 \) and passing through \( (-3, -2) \) is:

\[ y = \boxed{5x + 13} \]

By working through these steps, students can learn to find the slope and equation of lines that are parallel to a given line.
Transcribed Image Text:### Finding the Slope and Equation of Parallel Lines **Finding the Slope** To determine the slope of a line that is parallel to the given line equation: \[ 5x - y = 7 \] First, convert the equation into slope-intercept form (\( y = mx + b \)): \[ 5x - y = 7 \] \[ -y = -5x + 7 \] \[ y = 5x - 7 \] From this, we can see that the slope (\( m \)) of the line is 5. \[ m = \boxed{5} \] **Finding the Equation of the Parallel Line** Next, to find the equation of a line in slope-intercept form that is parallel to \( 5x - y = 7 \) and passes through the point \( (-3, -2) \): 1. We know the slope (\( m \)) is the same: 5. 2. Substitute the slope (\( m = 5 \)) and the given point \( (x_1, y_1) = (-3, -2) \) into the point-slope form of the line equation: \[ y - y_1 = m(x - x_1) \] \[ y - (-2) = 5(x - (-3)) \] \[ y + 2 = 5(x + 3) \] \[ y + 2 = 5x + 15 \] \[ y = 5x + 13 \] Hence, the equation of the line parallel to \( 5x - y = 7 \) and passing through \( (-3, -2) \) is: \[ y = \boxed{5x + 13} \] By working through these steps, students can learn to find the slope and equation of lines that are parallel to a given line.
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