The skateboarder in the figure is coasting down a ramp, and there are three forces acting on her: her weight W (magnitude = 685 N), a frictional force f (magnitude = 207N) that opposes her motion, and a normal force FN (magnitude = 599 N). Determine the net work done (a) by the weight W, (b) by the frictional force f , and (c) by the normal force FN when she coasts for a distance of 11.9 m. FN e =61.0°. W Weight component 29.0° W e = 180.0° (a) e = 90.0° (b)
The skateboarder in the figure is coasting down a ramp, and there are three forces acting on her: her weight W (magnitude = 685 N), a frictional force f (magnitude = 207N) that opposes her motion, and a normal force FN (magnitude = 599 N). Determine the net work done (a) by the weight W, (b) by the frictional force f , and (c) by the normal force FN when she coasts for a distance of 11.9 m. FN e =61.0°. W Weight component 29.0° W e = 180.0° (a) e = 90.0° (b)
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Transcribed Image Text:The skateboarder in the figure is coasting down a ramp, and there are three forces acting on her: her weight W (magnitude = 685 N),
a frictional force f (magnitude = 207N) that opposes her motion, and a normal force FN (magnitude = 599 N). Determine the net
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work done (a) by the weight W, (b) by the frictional force f , and (c) by the normal force FN when she coasts for a distance of 11.9
m.
FN
e =61.0
Weight component
29.0°
W
e = 180.0°
(a)
FN
e = 90.0°
(b)
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