The skateboarder in the figure is coasting down a ramp, and there are three forces acting on her: her weight W (magnitude = 665 N), a frictional force (magnitude = 148N) that opposes her motion, and a normal force FN (magnitude = 612 N). Determine the net work done (a) by the weight W, (b) by the frictional force, and (c) by the normal force when she coasts for a distance of 10.5 m. 23.0 (a) FN e-67.0 e 180.0° Ś Weight component FN 0=90.0°
The skateboarder in the figure is coasting down a ramp, and there are three forces acting on her: her weight W (magnitude = 665 N), a frictional force (magnitude = 148N) that opposes her motion, and a normal force FN (magnitude = 612 N). Determine the net work done (a) by the weight W, (b) by the frictional force, and (c) by the normal force when she coasts for a distance of 10.5 m. 23.0 (a) FN e-67.0 e 180.0° Ś Weight component FN 0=90.0°
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Transcribed Image Text:The skateboarder in the figure is coasting down a ramp, and there are three forces acting on her: her weight W (magnitude = 665 N), a
(magnitude = 612 N). Determine the net work
frictional force (magnitude = 148N) that opposes her motion, and a normal force
done (a) by the weight W. (b) by the frictional force, and (c) by the normal force when she coasts for a distance of 10.5 m.
N
f
23.0°
(a)
W
e-67.0°
W
= 180.0°
Weight component
(b)
FN
0=90.0°
Ś
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