The six arrows shown below have been shot straight up into the air from the same height. Ignore air resistance. Rank these arrows on the basis of acceleration when they are halfway to maximum height. E в 10 m/s 16 m/s 18 m/s 12 m/s 16 m/s 12 m/s 120 g 90 g 180 g 100 g 75 g 75 g A. all accelerations are zero O B. B > E > C > F>A =D O C.C>A = F > B = D > E O D. A = B = C = D = E = F (and are not zero) O E. none of the above
The six arrows shown below have been shot straight up into the air from the same height. Ignore air resistance. Rank these arrows on the basis of acceleration when they are halfway to maximum height. E в 10 m/s 16 m/s 18 m/s 12 m/s 16 m/s 12 m/s 120 g 90 g 180 g 100 g 75 g 75 g A. all accelerations are zero O B. B > E > C > F>A =D O C.C>A = F > B = D > E O D. A = B = C = D = E = F (and are not zero) O E. none of the above
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:The image shows six arrows, labeled A to F, that have been shot straight up into the air from the same height. We are to rank these arrows based on their acceleration when they are halfway to their maximum height, ignoring air resistance.
The details of each arrow are as follows:
- **Arrow A**: Velocity = 16 m/s, Mass = 75 g
- **Arrow B**: Velocity = 12 m/s, Mass = 180 g
- **Arrow C**: Velocity = 18 m/s, Mass = 100 g
- **Arrow D**: Velocity = 12 m/s, Mass = 75 g
- **Arrow E**: Velocity = 10 m/s, Mass = 120 g
- **Arrow F**: Velocity = 16 m/s, Mass = 90 g
The options for ranking by acceleration are:
A. All accelerations are zero
B. B > E > C > F > A = D
C. C > A = F > B = D > E
D. A = B = C = D = E = F (and are not zero)
E. None of the above
**Explanation**:
All arrows experience the same gravitational acceleration, 9.8 m/s² downward, regardless of their mass or initial velocity, when air resistance is ignored. Therefore, the correct choice is D, indicating that all accelerations are equal and not zero.
![**Question 4**
Refer to the position vs. time graph below. What is the instantaneous velocity of the object at 35 s?
(Graph explanation: The graph is a straight line showing position \(x\) in meters plotted against time \(t\) in seconds. The line starts at approximately (0, 10) and extends to (50, 40).)
- **Options**:
- A. 0 m/s
- B. 0.6 m/s
- C. -0.6 m/s
- D. 0.8 m/s
- E. none of the above
To calculate the instantaneous velocity at 35 s, determine the slope of the line, which is constant throughout. The slope \(m\) is calculated using the formula:
\[ m = \frac{\Delta y}{\Delta x} = \frac{40 - 10}{50 - 0} = \frac{30}{50} = 0.6 \, \text{m/s} \]
Thus, the correct answer is **B. 0.6 m/s**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbe8fa3d5-9008-42ca-a40d-155ab43de8c8%2Fa01368be-c70a-4153-b09a-ee917045a183%2F1hpytze_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 4**
Refer to the position vs. time graph below. What is the instantaneous velocity of the object at 35 s?
(Graph explanation: The graph is a straight line showing position \(x\) in meters plotted against time \(t\) in seconds. The line starts at approximately (0, 10) and extends to (50, 40).)
- **Options**:
- A. 0 m/s
- B. 0.6 m/s
- C. -0.6 m/s
- D. 0.8 m/s
- E. none of the above
To calculate the instantaneous velocity at 35 s, determine the slope of the line, which is constant throughout. The slope \(m\) is calculated using the formula:
\[ m = \frac{\Delta y}{\Delta x} = \frac{40 - 10}{50 - 0} = \frac{30}{50} = 0.6 \, \text{m/s} \]
Thus, the correct answer is **B. 0.6 m/s**.
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