The simply supported beam is subjected to the force F = 730 N and the uniform distributed load with intensity w = 140 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(x) and M(x). Take x = 0 at point A. F 2013 Michael Swanbom BY NC SA A B Vc D a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 4.60 m 3.22 m 2.76 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: V(x)= N and M(x)= N-m. In section CD: V(x)= N and M(x)= N-m.
The simply supported beam is subjected to the force F = 730 N and the uniform distributed load with intensity w = 140 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(x) and M(x). Take x = 0 at point A. F 2013 Michael Swanbom BY NC SA A B Vc D a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 4.60 m 3.22 m 2.76 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: V(x)= N and M(x)= N-m. In section CD: V(x)= N and M(x)= N-m.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The simply supported beam is subjected to the force F = 730 N and the uniform distributed load with
intensity w = 140 N/m. Draw the shear force and bending moment diagrams (in your homework
documentation) and determine the equations for V(x) and M(x). Take a = 0 at point A.
F
2013 Michael Swanbom
W
BY NC SA
B
D
a
Values for dimensions on the figure are given in the following table. Note the figure may not be to scale.
Variable Value
a
4.60 m
3.22 m
2.76 m
Support Reactions
The reaction at A is
N.
The reaction at D is
N.
Shear Force and Bending Moment Equations
In section AB:
V(x)=
N and M(x)=
N-m.
In section BC:
V(x)=
N and M(x)=
N-m.
In section CD:
V(x)=
N and M(x)=
N-m.
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